For their CD collections, Alan, Tom, and Barbara have a total of 52 CD’s. If Barbara had 6 more, then she would have as many as both of the boys together. Tom has three more CD’s than Alan. How many CD’s does each of the three have?
We can write three equations using the given information. Let A be the number of CDs that Alan has, T be Tom's number of CDs and B be Barbara's number of CDs. A + T + B = 52 ..........(1) B + 6 = A + T ............(2) T - 3 = A ...................(3) Do you follow, so far?
Yes:)
Do you have any ideas on how to solve these equations?
Breaking it down like that helped but I am still very lost when it comes to actually solving it.
One way to solve is to rearrange (2) as follows: B + 6 = A + T ............(2) Rearranging we get A + T - B = 6 ............(4) Now if we add equations (1) and (4) can you find the result?
Add these: A + T + B = 52 ..........(1) A + T - B = 6 ............(4)
So would A + T equal 46? Then would I just divide by two then take 3 from A and add it to T?
Adding (1) and (4) gives: 2A + 2T = 58 ...........(5) Do you follow?
Oh, okay. Yes I'm following.
Equation (3) gives A in terms of T A = T - 3 Therefore we can substitute for A in equation (5) giving: 2(T - 3) + 2T = 58 ..........(6) Can you solve (6) to find the value of T?
So T=16?
Correct. Good work! Now substitute your value for T into (3) to find the value of A: T - 3 = A ...................(3)
A= 13 T=16 B=23 Correct?
Correct. Well done!
Alright, thank you so much for your help! :)
You're welcome :)
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