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Physics 15 Online
OpenStudy (anonymous):

Beth has built a simple series circuit using wire, a battery, a lightbulb, and a switch. The bulb, however, does not light up when the switch is closed. Which describes a step that will help troubleshoot and work toward the solution of this problem? A. Change the wiring scheme to parallel. B. Use an electrical meter to test the voltage of the battery. C. Reverse the way the wire is connected to the poles of the battery. D. Shorten the length of wire between the battery and the switch

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

@JoKeR0331

OpenStudy (anonymous):

@Kitten_is_back

OpenStudy (shamim):

2 parallel resistance have same potential dial difference

OpenStudy (shamim):

And each of those 2 resistor has same potential difference as the battery

OpenStudy (shamim):

So each resistance connected in parallel will get enough potential difference

OpenStudy (shamim):

But if we connect 2 or more resistance in series, then the sum of potential difference of each resistance is equal the potential difference of battery

OpenStudy (shamim):

So potential difference across any resistor connected in series is much less than the potential difference of battery

OpenStudy (shamim):

U know longer wire has more resistance than the resistance of shorter wire

OpenStudy (amistre64):

what steps would YOU take? Which one of them is listed?

OpenStudy (shamim):

D? @amistre64

OpenStudy (amistre64):

its either the bulb, the switch, a connection in the wire, or a battery issue.

OpenStudy (shamim):

I think the whole connecting wire should b shorter

OpenStudy (shamim):

So the resistance of wire will b less

OpenStudy (shamim):

So the potential difference across the whole wire will b low

OpenStudy (shamim):

And the potential difference across the bulb will b higher to light up

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