SOMEBODY HELP!!!!!!!!!!!!!
In the function f(x)=6x-11..... How does a decrease of 1 in the independent variable x affect f(x)? A. f(x) will have an increase of 17 B. f(x) will have a decrease of 6x-6 C. f(x) will have a decrease of 6 D. f(x) will have an increase of 6
Ok, wait.
THANK YOU!!!
@jagr2713
the linearization of f(x) = x^4 + 3x^2 with a = -1 is L(x) = 4 - 10(x+1) the linearization formula is L(x) = f(a) + f'(a)*(x-a) when, a = -1 f(a) = (-1)^4 + 3(-1)^2 = 4 f'(x) = 4*x^3 + 6*x f'(a) = 4(-1)^3 + 6(-1) = -10 so, L(x) = (4) + (-10)*(x-(-1)) = 4 - 10(x+1)
So what is the answer... a,b,c or d?
@pooja195
Figure that out from the above equation.
I'll try too.
kash... I gave you a straight up answer on an English question.....
That wasn't me, it was @abenahsocute99
I think it is c
Well, you can thank me with a medal!
Is it C vocaloid?
I really need your help on this LAST question @Vocaloid
@Schen421 do you understand this one?
yeah, it's C
Ok great! Thank you!
how do u justify its C?
@xapproachesinfinity Well, this is how I approached the problem: the independent variable is x, so decreasing the independent variable by 1 means substituting (x-1) for x into the original function if f(x) = 6x - 11, then f(x-1) = 6(x-1) - 11 = 6x - 6 - 11 = 6x - 17 f(x-1) is 6 less than f(x), so I went with C
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