A 39 gram sample of a substance that's a by-product of fireworks has a k-value of 0.1024. N = N0e -kt N0 = initial mass (at time t = 0) N = mass at time t k = a positive constant that depends on the substance itself and on the units used to measure time t = time, in days Find the substance's half-life, in days. Round your answer to the nearest tenth.
please help
@puppylover52
srry idk this one
the equation is \[\frac{N(t)}{N_o} = e^{-kt}\] set N /No to 1/2 and that is what half life means, the time for the amount to halve \[\frac{1}{2} = e^{-0.1024T}\] take logs and solve for T, where t = T is the half life
nice work @IrishBoy123 !
so the answer cause I cant solve it?
@IrishBoy123 @Jack1
i solved for t and its still not it
i think u use t to solve the 1/2 life... yeah?
no, in irish's example: t is the half life
can you find the answer @Jack1 ?
yeah, i have the answer, what did u get for t?
like 6.790
yep, same here, exact answer for half life is t=6.76902 ish
all i have is grams tho, i don't know the units of k, so i have no idea of the units of t or if k and t are both in the same units of measure...?
(eg if k's relates to pounds/second or something and our No is in grams we have a problem)
so you think you can solve it?
@IrishBoy123
lol... wat? so 6.8 isnt ur answer? (rounded to the nearest tenth)
lol it is now my computer got messed up so it was saying everything incorrect thanks @Jack1
ha. s'cool ;)
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