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Mathematics 7 Online
OpenStudy (anonymous):

will fan and medal but need help ASAP!!

OpenStudy (anonymous):

The function H(t) = -16t2 + vt + s shows the height H (t), in feet, of a projectile launched vertically from s feet above the ground after t seconds. The initial speed of the projectile is v feet per second. Part A: The projectile was launched from a height of 100 feet with an initial velocity of 60 feet per second. Create an equation to find the time taken by the projectile to fall on the ground. (2 points) Part B: What is the maximum height that the projectile will reach? Show your work. (2 points) Part C: Another object moves in the air along the path of g(t) = 20 + 38.7t where g(t) is the height, in feet, of the object from the ground at time t seconds. Use a table to find the approximate solution to the equation H(t) = g(t), and explain what the solution represents in the context of the problem? [Use the function H(t) obtained in Part A, and estimate using integer values] (4 points) Part D: Do H(t) and g(t) intersect when the projectile is going up or down, and how do you know? (2 points)

OpenStudy (pinklion23):

this is a unit test in math we can not help with tests :(

OpenStudy (anonymous):

what exactly are you having trouble with

OpenStudy (pinklion23):

she wants us to help her answer a test from k12 trust me i had the question before :(

OpenStudy (anonymous):

actualy no I do not go to k12

OpenStudy (anonymous):

if she asks about it in a right way, there is no problem to help getting to the solution

OpenStudy (anonymous):

and I was asking if you could check what I have so far.

OpenStudy (anonymous):

thats the right question

OpenStudy (pinklion23):

ok sounds good so what is the first question you have

OpenStudy (anonymous):

the equation that I cam up with for part a is h(t)=16(60)^2+100(60)

OpenStudy (anonymous):

I have the feeling that its wrong but I am not sure

OpenStudy (anonymous):

**came**

OpenStudy (pinklion23):

ok well i got tagged in something im sure myko can help you so good day : )

OpenStudy (anonymous):

ok, do you think you can help me @myko

OpenStudy (anonymous):

just ask and we will see

OpenStudy (anonymous):

the equation that I came up with for part a is h(t)=16(60)^2+100(60)

OpenStudy (anonymous):

did I do it right or is there an error

OpenStudy (anonymous):

Hmm. It is not correct. |dw:1432914354831:dw| The given equation represents the parabola openning downwards. Also it says that that will be the path folowed by the projectile if you take coordinate axis in a usual way. So imagine it being the actual trajectory of your particle. The parabola will cut t-axis in two points. One of them is the moment when it hits the ground, right?

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