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Chemistry 6 Online
OpenStudy (adajiamcneal):

@Teddyiswatshecallsme

OpenStudy (adajiamcneal):

OpenStudy (teddyiswatshecallsme):

For 1 is that 569?

OpenStudy (teddyiswatshecallsme):

569 milliliters of solution?

OpenStudy (adajiamcneal):

yes

OpenStudy (teddyiswatshecallsme):

k den.

OpenStudy (teddyiswatshecallsme):

The molarity of a solution containing 7.0 moles of solute in 569mL of solution is a)81Mb)0.081Mc)12MD)4.0MThe answer is C. 12M 7 x 1000/569 = 12.302

OpenStudy (adajiamcneal):

ok thank you :) do you know how to do 17?

OpenStudy (teddyiswatshecallsme):

Mhmmm. Hold on a second. :)

OpenStudy (teddyiswatshecallsme):

Percent volume = (volume of solute / volume of solution) x 100% Both A and B use g or grams as the unit for your solute so both are wrong as we need volume units to get percent volume. Both C and D use volume unit, mL or milliliters so these are are only remaining choices. However, in choice C, it says solute/solvent. What we need is solute / solution, which is shown in D. Therefore, the answer is D. :)

OpenStudy (adajiamcneal):

ok thank you so much :) if i need more ill tagg you :)

OpenStudy (teddyiswatshecallsme):

You're so welcome :D, and alright... :)

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