Question

problem attached inside!

Answer 1

@Michele_Laino do you understand this one perhaps? :)

Answer 2

yes! That is nuclear physics

Answer 3

yay:)

Answer 4

as we can see the atomic number is increased, so the number of protons is increased

Answer 5

Z is going from 88 to 89

Answer 6

Z is the atomic number or proton number

Answer 7

what is happened inside the nucleus of Ra?

Answer 8

here is the nuclear process occurred inside that nucleus:

Answer 9

\[\Large n \to p + {e^ - } + {\bar \nu _e}\]

Answer 10

i am not sure.... :/

so for the first part, the complete equation is what you wrote above? or is that just the formula?

Answer 11

namely a neutron is transformed itself in a proton plus an electron plus an anti-neutrinos

Answer 12

you have to write e^-, namely electron, and the radiation involved is the
\[\Large {\beta ^ - }\] radiation

Answer 13

ooh okay!!

Answer 14

since \[\Large {\beta ^ + }\] radiation is associated to an emission of positrons

Answer 15

ahh okay:)

Answer 16

ok! :)

Answer 17

so the first part asks for the complete equation, right? what is that? :/

Answer 18

complete equation is:

Answer 19

\[\Large {}_{88}^{228}Ra \to {}_{ - 1}^0{e^ - } + {}_{89}^{228}Ac\]

Answer 20

ohhh okay! awesome! so the next part asks for type of radiation given off in this reaction? how can we find that?

Answer 21

radiation is \[\Large {\beta ^ - }\] radiation

Answer 22

what is that symbol called again? is it just radiation? I forgot :(

Answer 23

we can conclude that the radiation involved is the \[\Large {\beta ^ - }\] radistion, since in a nuclear reaction electric charge is conserved

Answer 24

it is this, corret? ß^- ?

Answer 25

this symbol:
\[\Large {\beta ^ - }\] stands for "beta minus radistion"

Answer 26

ohhh okay :D

Answer 27

oops.. stands for "beta minus radiation"

Answer 28

and so the last part asks where the particle comes from and the process of this kind of decay? how do i find that?

Answer 29

:)

Answer 30

it is a classic nuclear reaction, you can find it into the most nuclear or particle physics textbooks. Here is my particle physics textbooks:
\[\Large \begin{gathered}
Title:{\text{Introduction To High Energy Physics}} \hfill \\
Author:{\text{D}}{\text{.H}}{\text{.Perkins}} \hfill \\
Publisher:{\text{Addison - Wesley}} \hfill \\
3rd - Edition \hfill \\
\end{gathered} \]

Answer 31

here is the involved nuclear reaction:
\[\Large n \to p + {e^ - } + {{\bar \nu }_e}\]
n=neutron
p= proton
\[{{\bar \nu }_e}\] = electronic anti-neutrinos
\[{e^ - }\] is the electron

Answer 32

oops..electronic anti-neutrino*

Answer 33

ahh okay!! :D and so that is where the particle comes from, right? and what about the decay?

Answer 34

the decay is the "beta-minus" decay

Answer 35

the decay type comes from the type of the emitted radiation from that decay

Answer 36

oh okay!! and so is that all for this problem? :O

Answer 37

we have many types of decays, namely
gamma decay, if there is an emission of photons,
alpha decay, if there is an emission of alpha particles

Answer 38

oohh:O

Answer 39

yes! we have finished!

Answer 40

yay!! thank you very much!! :D

Answer 41

thank you!! :D