Question

find the LCD of booth fractions and then simplify the expression completly assume the denominator equils 0
2x 3y
____ - ______
6x^3y 4xy^2

Answer 1

this could help with finding the LCD http://www.helpwithfractions.com/math-homework-helper/least-common-denominator/

Answer 2

ok let me check it out

Answer 3

can you do live help please

Answer 4

live help?

Answer 5

yea like help me now walk through it with me it is easyer

Answer 6

okay. well for this question, when you say to assume that the denominator equals zero, does that mean to just completely avoid the bottom of each fractions?

Answer 7

idk

Answer 8

we can rewrite your expression as below:
\[\Large \frac{{2x}}{{6{x^3}y}} - \frac{{3y}}{{4x{y^2}}} = \frac{1}{{3{x^2}y}} - \frac{3}{{4xy}}\]

Answer 9

what did u take out?

Answer 10

The LCD is the smallest number or expression that is divisible by both denominators.
You need to take each part of it at a time.
Let's look at the numbers, then the x's then the y's.

What is the smallest number that is divisible by both 3 and 6. In other words, what is the LCM of 3 and 6?

Answer 11

3

Answer 12

No, it is 6

Answer 13

we have to compute the LCM between:
\[\Large 3{x^2}y,\quad and\quad 4xy\]

Answer 14

This means that the number part we need for the LCD is 6.

Now let's look at the x's.
There is an x^2 and an x.
The lowest expression that will divide both x^2 and x is x^2, so we need x^2 for the LCD.

Now let's look at the y part.
You have y and y^3.
The simplest expression with y that will divide evenly by y and y^3 is y^3, so you need y^3 in the LCD.

Once you put together the number part, the x part and rthe y part, you end up with:
LCD = 6x^2y^3

Answer 15

I am so confused I have 2 diffrent ppl telling me 2 different things

Answer 16

I'm not sure where the other person is going with their answer but mine are clear and simple

Answer 17

ok

Answer 18

I'm sure that my procedure is the right procedure

Answer 19

.... aren't you a qualified helper lol

Answer 20

ook

Answer 21

but mine is correct I'm sure

Answer 22

ok! Then please continue! @aaldia678

Answer 23

I want to know what each of ur answers r

Answer 24

@Michele_Laino thank you

Answer 25

reread what I wrote @sarahefal

Answer 26

ok

Answer 27

wait I'm sorry, I used the wrong number

Answer 28

ok

Answer 29

this is your equation right?

\[\frac{ 2 }{ 6x ^{3y} } -\frac{ 3y }{ 4xy ^{2}}\]

Answer 30

okay so what is the LCD of 6 and 4? figure that out first

Answer 31

3*2^2

Answer 32

?

Answer 33

the LCD

Answer 34

so 12

Answer 35

Correct. The smallest number that is divisible by both 4 and 6 is 12,
That means the number part we need for the LCD is 12

Answer 36

then what?

Answer 37

Now let's look at the x's.
There is an x^3 and an x.
The lowest expression that will divide both x^3 and x is x^3, so we need x^3 for the LCD.

Answer 38

Now let's look at the y part.
You have y and y^2.
The simplest expression with y that will divide evenly by y and y^2 is y^2, so you need y^2 in the LCD.

Answer 39

ok so it is 12x^3y^2

Answer 40

yes!!

Answer 41

that's right!

Answer 42

:) thank you

Answer 43

good job! @aaldia678

Answer 44

hb the numerators?

Answer 45

12x^3y^2 is the final answer right. you just needed the LCD

Answer 46

whatttt

Answer 47

we have to simplify the expression above

Answer 48

btw it is assume no denomiator =0

Answer 49

yes!

Answer 50

so what is the numerator if we found the denominator

Answer 51

\[\left(\begin{matrix}2x \\ 0\end{matrix}\right) - \frac{ 3y }{ 0}\] so this is the equation that needs to be simplified?

Answer 52

sorry, that first part came out weird

Answer 53

no denominator =0 and thats ok

Answer 54

no one of the denominators can be equal to zero @aaldia678

Answer 55

thx @Michele_Laino

Answer 56

hmm okay so what would be the full answer?

Answer 57

step #1 we have to compute this division:
\[\Large \frac{{12{x^3}{y^2}}}{{2x}} = ...?\]

Answer 58

my question is why is the 12 term the numerator?

Answer 59

that equals 6x^2y^2

Answer 60

ok! now we have to multiply the first numerator by 6x^2y^2, namely, what is:
\[\Large 2x \cdot 6{x^2}{y^2} = ...?\]

Answer 61

12x^3y^2

Answer 62

here is wha we are doing: