Question

will fan and medal but need help ASAP!

Answer 1

A basketball is thrown upwards. The height f(t), in feet, of the basketball at time t, in seconds, is given by the following function:

f(t) = -16t^2 + 44t + 12

Which of the following is a reasonable domain of the graph of the function when the basketball falls from its maximum height to the ground?

-0.25 < t < 2
0 < t < 3
1 < t < 2.4
1.4 < t < 3

Answer 2

@BPDlkeme234
@is3535

Answer 3

@Thesmarterone

Answer 4

It reaches a maximum height at F(t) = 0 [dont ask me why]
so make the function equal to zero and solve for t

Answer 5

0=-16t^2+44t+12

Answer 6

I got 3 and -1/4

Answer 7

my mistake @gabymarie313 , @DanJS had probably worked that out, its at dy/dt=0 that it reaches a maximum height

Answer 8

so how would I solve it?

Answer 9

first we will find it at the bottom i.e. let t=0
f(0)= -16(0)^2 +44 + 12

Answer 10

f(0) = 44 + 12
f(0) = 56

Answer 11

so is the the maximum height?

Answer 12

maximum height occurs where balls stops, ball stops at dy/dt = 0

Answer 13

dy/dt = 2 (-16t) + 44 = -18t + 44

Answer 14

-18t + 44 = 0
-18t = -44
18 t = 44
t=44/18
t = 2.44

Answer 15

I get it now. Thank you for your time.

Answer 16

do you think you can help me with a couple more @BPDlkeme234

Answer 17

go for it!

Answer 18

Matt sells burgers and sandwiches. The daily cost of making burgers is $520 more than the difference between the square of the number of burgers sold and 30 times the number of burgers sold. The daily cost of making sandwiches is modeled by the following equation:

C(x) = 2x^2 - 40x + 300

C(x) is the cost in dollars of selling x sandwiches.

Which statement best compares the minimum daily cost of making burgers and sandwiches?

It is greater for sandwiches than burgers because the approximate minimum cost is $250 for burgers and $292 for sandwiches.
It is greater for sandwiches than burgers because the approximate minimum cost is $100 for burgers and $295 for sandwiches.
It is greater for burgers than sandwiches because the approximate minimum cost is $295 for burgers and $100 for sandwiches.
It is greater for burgers than sandwiches because the approximate minimum cost is $292 for burgers and $250 for sandwiches.

Answer 19

so how would I solve it ?

Answer 20

When I modelled the burgers I got
C(burger) = [(burgers sold)^2 - 30(burgers sold)] + $520

Answer 21

this is very similar to the equation for the sandwiches

Answer 22

now, you can put these under each other and solve:
C(x) = 2x^2 -40x +30
C(x) = x^2 - 30x +520

Answer 23

now these are two quafratic equations , and will intersect each other

Answer 24

do I solve for x?

Answer 25

or do I use the quadratic formula?

Answer 26

are you still there @BPDlkeme234 ?

Answer 27

do I solve for x or do I use the quadratic formula to solve?

Answer 28

@Thesmarterone