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Mathematics 16 Online
OpenStudy (ayyookyndall):

Help

OpenStudy (meowlover17):

Think of the diameter as a line, solve for the midpoint of that line to find the center.

OpenStudy (meowlover17):

And the radius is basically the length from the midpoint to the end of the circle, in this case being one of the other coordinates.

OpenStudy (meowlover17):

The formula would be

OpenStudy (meowlover17):

http://www.purplemath.com/modules/midpoint.htm here

OpenStudy (meowlover17):

Good luck thats all the information i can give.

jimthompson5910 (jim_thompson5910):

where are you stuck? are you stuck on the formula given on the page MeowLover17 gave you?

OpenStudy (ayyookyndall):

Yes, putting it in.

jimthompson5910 (jim_thompson5910):

P(-10,-2) and Q(4,6) the x coordinates of each point are -10 and 4 add them up: -10+4 = -6 divide the result by 2: -6/2 = -3 so the x coordinate of the midpoint is x = -3 Do the same for the y coordinates to get the y coordinate of the midpoint

jimthompson5910 (jim_thompson5910):

very good

OpenStudy (ayyookyndall):

Thats it for Part A?

jimthompson5910 (jim_thompson5910):

so that's effectively what this formula \[\LARGE (x_m, y_m) = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)\] is saying "add up the corresponding coordinates and divide by 2 to get the midpoint "

OpenStudy (ayyookyndall):

Okay, got it. :-)

jimthompson5910 (jim_thompson5910):

yes the midpoint of P and Q is the center because P and Q lie on the same diameter |dw:1432945083421:dw|

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