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Chemistry 20 Online
OpenStudy (vera_ewing):

chem

OpenStudy (vera_ewing):

OpenStudy (vera_ewing):

@JoannaBlackwelder A or B?

OpenStudy (joannablackwelder):

Yep, I get one of those.

OpenStudy (anonymous):

Sorry been a while, I am more of organic, but I figured it out. I got 1.42m

OpenStudy (joannablackwelder):

Hm, that's not what I got.

OpenStudy (joannablackwelder):

Did you do it like this?

OpenStudy (anonymous):

2HI--> H2 +I2 I 1.6m 0 0 C -x X X E 1.6x X X k=x^2/ (1.6-x)^2 k=1.42m

OpenStudy (anonymous):

Make snese

OpenStudy (joannablackwelder):

No, I get the equilibrium expression for HI to be 1.6-2x

OpenStudy (joannablackwelder):

Since 2 moles of it decompose for each 1 mole of H2 and I2

OpenStudy (anonymous):

Remember 2 moles HI so ()^2

OpenStudy (anonymous):

Look at my work

OpenStudy (anonymous):

2HI intial, when you have any number of moles you take it to the the power, example 3HI then (HI)^3

OpenStudy (anonymous):

@n648c788 what chemistry classes have you taken?

OpenStudy (anonymous):

The decompsition just means you will make the HI -x, and H x, Ix

OpenStudy (anonymous):

All but Organic is what I know best, but If I see examples I can solve old problems

OpenStudy (anonymous):

HI would be -2x not -x

OpenStudy (anonymous):

Yeah you are right little error, but it is worked the same way

OpenStudy (anonymous):

Sorry internet is bad, but you did it, you used quadratic equation at end right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Awseome job, sorry its been a while

OpenStudy (anonymous):

Are you ok? seems the task is done

OpenStudy (anonymous):

@vera_ewing is offline

OpenStudy (anonymous):

Oh ok thanks I appreciate it!

OpenStudy (anonymous):

Yes do you need any help

OpenStudy (anonymous):

ya I have a chem question posted above

OpenStudy (anonymous):

Ok

OpenStudy (vera_ewing):

Joanna is correct.

OpenStudy (joannablackwelder):

:-) Thanks for the feedback, Vera.

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