Chemistry
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OpenStudy (vera_ewing):
chem
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OpenStudy (vera_ewing):
OpenStudy (vera_ewing):
@JoannaBlackwelder A or B?
OpenStudy (joannablackwelder):
Yep, I get one of those.
OpenStudy (anonymous):
Sorry been a while, I am more of organic, but I figured it out. I got 1.42m
OpenStudy (joannablackwelder):
Hm, that's not what I got.
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OpenStudy (joannablackwelder):
Did you do it like this?
OpenStudy (anonymous):
2HI--> H2 +I2
I 1.6m 0 0
C -x X X
E 1.6x X X
k=x^2/ (1.6-x)^2
k=1.42m
OpenStudy (anonymous):
Make snese
OpenStudy (joannablackwelder):
No, I get the equilibrium expression for HI to be 1.6-2x
OpenStudy (joannablackwelder):
Since 2 moles of it decompose for each 1 mole of H2 and I2
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OpenStudy (anonymous):
Remember 2 moles HI so ()^2
OpenStudy (anonymous):
Look at my work
OpenStudy (anonymous):
2HI intial, when you have any number of moles you take it to the the power, example 3HI then (HI)^3
OpenStudy (anonymous):
@n648c788 what chemistry classes have you taken?
OpenStudy (anonymous):
The decompsition just means you will make the HI -x, and H x, Ix
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OpenStudy (anonymous):
All but Organic is what I know best, but If I see examples I can solve old problems
OpenStudy (anonymous):
HI would be -2x not -x
OpenStudy (anonymous):
Yeah you are right little error, but it is worked the same way
OpenStudy (anonymous):
Sorry internet is bad, but you did it, you used quadratic equation at end right?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
Awseome job, sorry its been a while
OpenStudy (anonymous):
Are you ok? seems the task is done
OpenStudy (anonymous):
@vera_ewing is offline
OpenStudy (anonymous):
Oh ok thanks I appreciate it!
OpenStudy (anonymous):
Yes do you need any help
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OpenStudy (anonymous):
ya I have a chem question posted above
OpenStudy (anonymous):
Ok
OpenStudy (vera_ewing):
Joanna is correct.
OpenStudy (joannablackwelder):
:-) Thanks for the feedback, Vera.