Question

How do you correct samples of gases to standard temperature?

Answer 1

I have;
622 cm^3 at 15.0 C
and another
55.6 dm^3 at 110 K

Answer 2

V2 = 589.6cm³ for #1
&
138.0 dm³ for #2

Answer 3

Use the formula: \(\large \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\)

For example, for the first set of conditions:

\(V_1\)=622 cm^3 \(T_1\)= 15.0 C + 273 = 288 K

\(V_2\)= unknown \(T_2\)= 273 K

\(\large \dfrac{622~ cm ^3}{288 ~K}=\dfrac{V_2}{273~K}\rightarrow V_2=\dfrac{273~K*622~ cm ^3}{288 ~K}=589.6~cm^3 \)

Answer 4

Thank you so much for explaining that! Sorry I didn't respond earlier I was working on something else.