1. what is the value of n so that the expression x^2+12x+n is a perfect square trinomial
a.6
b.36
c.72
d.144
2. what are the solutions of the equation x^2+4x=96
a.2,-48
b.-12,8
c.-2,48
d12,-8

Question

1. what is the value of n so that the expression x^2+12x+n is a perfect square trinomial
a.6
b.36
c.72
d.144
2. what are the solutions of the equation x^2+4x=96
a.2,-48
b.-12,8
c.-2,48
d12,-8

loser66 · Answer

Any idea?

anonymous · Answer

I think 1 is b and I have no idea on 2 @Loser66

luigi0210 · Answer

Yes, you would be right on 1, to get it to be a perfect square you take b and.. $\Large (\frac{ b}{2})^2 $ 

For 2, set it equal to zero to solve.

anonymous · Answer

so it would be c

luigi0210 · Answer

c? Nope: 

x=-2, 48

$(x+2)(x-48)=0 $ 

$x^2-48x+2x-96$

$\Large =x^2-46x-96$)