Question

1. what is the value of n so that the expression x^2+12x+n is a perfect square trinomial
a.6
b.36
c.72
d.144
2. what are the solutions of the equation x^2+4x=96
a.2,-48
b.-12,8
c.-2,48
d12,-8

Answer 1

Any idea?

Answer 2

I think 1 is b and I have no idea on 2 @Loser66

Answer 3

Yes, you would be right on 1, to get it to be a perfect square you take b and.. \(\Large (\frac{ b}{2})^2 \)

For 2, set it equal to zero to solve.

Answer 4

so it would be c

Answer 5

c? Nope:

x=-2, 48

\((x+2)(x-48)=0 \)

\(x^2-48x+2x-96\)

\(\Large =x^2-46x-96\))