Question

A man pushes a lawn mower with a force of 34 lb exerted at an angle of 30° to the ground. Find the horizontal and vertical components of the force. (Assume that the horizontal direction is positive and the vertical direction is negative.)

Answer 1

I got 17sq3i-17j

Answer 2

but it doesn't want it

Answer 3

Suggest you use geometry.
You have a right triangle with the hypothenuse as your force of 32 lbs. The gravity/(vertical component) would be sin 30 degrees x 32.
The horizontal component will be cos 30 degrees x 32.
=( sqrt of 3) x 16.

Answer 4

where did you get 32?

Answer 5

equation of force is
F=fcos(theta)i+fsin(theta)j
right?

Answer 6

That is the vector components yea, the i=<1,0> is the X direction, and the j=<0,1> is the y direction component

Answer 7

calculate each, Magnitude of F times cos(theta) for the x component, and magnitude of F times sin(theta) for the Y component

Answer 8

So then plugging numbers in we have:
34cos(30)i+34sin(30)j

Answer 9

simplifies to:
34(sq3/2)i+34(1/2)j

Answer 10

is that all correct?

Answer 11

\[F _{Tot}=F _{x}i+F _{y}j\]

Answer 12

yes, just calculate Fx and Fy, those are the legs of the triangle, the components of the force

Answer 13

um then the answer will be:
\[17\sqrt{3}i+17j\]

Answer 14

Yeah? but they don't accept that answer

Answer 15

The vertical direction (UP) is said to be negative, so that component will be negative

Answer 16

oh sorry, right right. I wrote it wrong in here but wrote it correct into the answer box :P they don't like it

Answer 17

\[17\sqrt{3}i-17j\]

Answer 18

yeah, that is the Force written in component form. Not sure how you are supposed to enter the answer though

Answer 19

hrm..yeah because that should be right and the example is written that way too.

Answer 20

Previous questions in this homework have also rejected anything that has i or j in it, i'll just ask my prof monday :) thanks!!

Answer 21

yw