A triangle is placed in a semicircle with a radius of 5 ft, as shown below. Find the area of the shaded region. Use the value 3.14 for pi and do not round your answer.
area of triangle\[=\frac{ 1 }{ 2 }\times base \times altitude=?\] area of semi circle\[=\frac{ \pi \times r^2 }{ 2 }=?\] then subtract
Do I find the answer for both
Do you know that area of circle is\[Area = πr^2\] and the area of triangle is \[Area of \triangle = \frac{ 1 }{ 2 } * base * height\] Then now what you have the two areas with your hands , to get the shaded region you just simply subtract the smaller shape from the larger one , which in this question Larger : the semicircle and the smaller one is the triangle ! Now to calculate just subs. with given values \[Area of semicircle = \frac{ 1 }{ 2 } * π * 5^2 = 12.5 \] And \[Area of \triangle = \frac{ 1 }{ 2 } * 10 * 5 = 25\] Now the shaded region is :\[Area of shaded region : 12.5π - 25\] Let me know if you got it :)
I completely understand :) so I subtract 12.5 pi - 25 and the answer is 14.26
@Omar_Elboredy
area of triangle\[=\frac{ 1 }{2 }\times10\times 5=25\] area of semi circle\[=\frac{ \pi r^2 }{ 2 }=\frac{ 3.14\times25 }{ 2 }=\frac{ 78.50 }{ 2 }=39.25\] reqd. area=39.25-25=?
Exactly ! :D
I have no idea who is right lol...
both are correct
@surjithayer would the answer be ft, ft^2 or ft^3?
area is always in square units
Thank you the both of ya'll!
if I could give you both metals I would!
Welcomes ! :) Feel free to ask anytime :D
Will you help me with one more? @Omar_Elboredy
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