Question

Calculate the discriminant and use it to determine how many real-number roots the equation has.

3x2 – 6x + 4 = 0

A.
three real-number roots

B.
no real-number roots

C.
one real-number root

D.
two real-number roots

Answer 1

Can you identify the values of a, b and c as @pooja195 showed you?

Answer 2

You'll need them to calculate the discriminant, which in turn is necessary to find the number of real/complex roots.

Answer 3

no real number trust me im in college I took all about this

Answer 4

3x^2,6x and 4

Answer 5

@mathmate

Answer 6

are you there? @mathmate

Answer 7

The powers of x do not count, because it comes from ax^2+bx+c, so a,b,c do not contain the powers of x, just the coefficients will do.

Answer 8

ok

Answer 9

But you need to include the signs, so it is
a=3,
b=-6
c=4

Answer 10

Can you look up the formula for discriminant, which @pooja195 gave you?

Answer 11

ummm, where do i get that? shes ofline im prety sure!!

Answer 12

Your previous post.

Answer 13

it doesnt let me for some reason , can you try??

Answer 14

ok, you'll be needing this for you test or exam, so try to get familiar with it, if you can:
discriminant = \(b^2-4ac\)

Answer 15

ok

Answer 16

if the discriminant is negative, all roots are complex.
If the discriminant is positive, there will be two distinct (different) real roots
if the discriminant is zero, there will be two coincident (same value) real roots.

Answer 17

okayyy!

Answer 18

so my guess is c? @mathmate

Answer 19

Please do not guess!
Did you calculate the determinant?

Answer 20

* discriminant