Find the solution of this system of equations. Seperate the x- and y-values with a comma. x=8+y -2x+6y=-20
Use substiotuion :)
\[\huge-2(8+y)+6y=-20\]
solve the first equation for 'y' then substitute into second equation.
I'm not good with this stuff at all lol
Distribute first \[\huge −2(8+y)\]
-16 - 2y
good :) \[\huge-16-2y+6y\] combine like terms
-16+4
no
-16+4y*
good \[4y-16=-20\] isolate y
I don't know how to do any of that haha, I'm just finishing a study guide I have so I can pass for the year :/
Well firt step to isolate would be to add the 16 to both sides :) -16+16=0 so it cancels -20+16=?
-4
good now just divide! :) 4y=-4 4/4=1 so you are left with y -4/4=?
-1
so it's 7, -1?
yep :) good job!
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