Question

Calculate the discriminant and use it to determine how many real-number roots the equation has.

3x2 – 6x + 4 = 0

A.
three real-number roots

B.
no real-number roots

C.
one real-number root

D.
two real-number roots

Answer 1

@jagr2713

Answer 2

@pooja195

Answer 3

@JoKeR0331 @KevinM.Williams159 @Lady.Liv1776 @Legends @sleepyjess @k142 @dan815 @desiraem @Samus_Aran

Answer 4

Three

Answer 5

I think?

Answer 6

can you tag someone else to see what they think to??

Answer 7

@Loser66

Answer 8

Can't be 3. the highest exponent is 2, so you there can only be 0, 1, or 2 solutions. The discriminant is b² - 4ac.

- If b² - 4ac = 0, there is 1 solution.
- If b² - 4ac is positive, there are 2 solutions.
- If b² - 4ac is negative, there are 0 solutions.

Answer 9

my answer whould be c?

Answer 10

@peachpi

Answer 11

No. What did you get for the discriminant.

Answer 12

sorry, i meant to say d!:)

Answer 13

I am with peachpi. They asked you to find discriminant. You MUST have it first.

Answer 14

i am not sure how to do that, will you helpme??

Answer 15

For the equation ax² + bx + c = 0, the discriminant is b² - 4ac. For your equation, a = 3, b = -6, and c = 4.

Answer 16

okay

Answer 17

So what's b²-4ac?

Answer 18

um is that the abc equation?? @peachpi

Answer 19

I'm not sure what the a,b,c equation is. I gave you the numbers above. You just need to plug them into the expression b²-4ac to get the discriminant.

Answer 20

-6^2-4(3)(4) @peachpi

Answer 21

is this correct? @peachpi

Answer 22

yes and now you need to simplify it to a single number.