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Chemistry 19 Online
OpenStudy (anonymous):

Electrochemistry

OpenStudy (anonymous):

Explain the reaction that would occur in a galvanic cell between solutions of Al3+ and Pb2+. Identify the oxidation and reduction reactions and the location of each reaction. Then, use the standard reduction potential tables to determine the cell potential.

OpenStudy (aaronq):

The direction of the spontaneous flow of electrons would be so that cell potential would be positive. This means that the cathode electrode has a larger reduction potential than the anode electrode. \(E^o_{cell}=E^o_{cathode}-E^o_{anode}\)

OpenStudy (anonymous):

so would aluminum be the cathode and lead the the anode?

OpenStudy (aaronq):

what are their reduction potentials?

OpenStudy (anonymous):

oh wait, I forgot they were negative so it is reversed. Aluminum is the anode (-1.66V) and Lead is the cathode (0.13V).

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