Question

Electrochemistry

Answer 1

Explain the reaction that would occur in a galvanic cell between solutions of Al3+ and Pb2+. Identify the oxidation and reduction reactions and the location of each reaction. Then, use the standard reduction potential tables to determine the cell potential.

Answer 2

The direction of the spontaneous flow of electrons would be so that cell potential would be positive. This means that the cathode electrode has a larger reduction potential than the anode electrode.

\(E^o_{cell}=E^o_{cathode}-E^o_{anode}\)

Answer 3

so would aluminum be the cathode and lead the the anode?

Answer 4

what are their reduction potentials?

Answer 5

oh wait, I forgot they were negative so it is reversed. Aluminum is the anode (-1.66V) and Lead is the cathode (0.13V).