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Electrochemistry
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Explain the reaction that would occur in a galvanic cell between solutions of Al3+ and Pb2+. Identify the oxidation and reduction reactions and the location of each reaction. Then, use the standard reduction potential tables to determine the cell potential.
The direction of the spontaneous flow of electrons would be so that cell potential would be positive. This means that the cathode electrode has a larger reduction potential than the anode electrode. \(E^o_{cell}=E^o_{cathode}-E^o_{anode}\)
so would aluminum be the cathode and lead the the anode?
what are their reduction potentials?
oh wait, I forgot they were negative so it is reversed. Aluminum is the anode (-1.66V) and Lead is the cathode (0.13V).
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