Question

please help. medal and fan

Answer 1

Consider a series circuit consisting of a resistor of R ohms, an inductor of L henries, and variable voltage source of V(t) volts (time t in seconds). The current through the circuit I(t) (in amperes) satisfies the differential equation:

dI/dt + (R/L)I = (1/L)V(t)

Find the solution to this equation with the initial condition I(0)=0, assuming that R=50Ω, L=5 H, and V(t) is constant with V(t)=10 V.

Answer 2

I'm having trouble differentiating it

Answer 3

I(e^(RT/L)) = integral: (V(t)e^(RT/L))/L

Answer 4

with the numbers plugged in
Ie^(10t) = integral: (V(t)e^(10t))/5

Answer 5

That's as far as I got

Answer 6

maybe treat V(t) as a constant?

Answer 7

@rational

Answer 8

I also plugged in 10 for V(t) and got -1/5 for C when I(0)=0.

Answer 9

i(r/L) this is constant,isn't it?

Answer 10

What do you mean?

Answer 11

because r/L is constant becasue r and L are constants

Answer 12

or i'm missing smth

Answer 13

ya when i plugged those values in I got e^10T

Answer 14

v(t) is also constant it's 10

Answer 15

yep, but the question is asking me to find an equation for V(t)

Answer 16

v(t)=10 this is equation

Answer 17

I wish it was, I already tried that lol

Answer 18

when it is writte above v(t)=10v v here is volt not a variable i guess

Answer 19

i think it is a constant but i'm not sure where i need to apply it

Answer 20

The only other part of the question is V(t) =

Answer 21

@triciaal

Answer 22

don't have the solution,
my input:
dl/dt = dl/dv*dv/dt

for some reason I would be separating the variables and integrating
when you integrate you add the constant
here the constant is given as 10V