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OpenStudy (bananas1234):
Divide and simplify completely. Assume that no denominator equals zero. d^2-1/d^2-d divided by d - 1/d
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OpenStudy (bananas1234):
@UnkleRhaukus
OpenStudy (unklerhaukus):
\[\frac{d^2-1}{d^2-d}\div\frac{d-1}d\\
=\frac{d^2-1}{d^2-d}\times\frac d{d-1}\\
=\]
OpenStudy (unklerhaukus):
factor the denominator of the first fraction . . .
OpenStudy (bananas1234):
d^2 @UnkleRhaukus
OpenStudy (unklerhaukus):
huh?
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OpenStudy (bananas1234):
d^2 - 1/d^2
OpenStudy (unklerhaukus):
what is that susposed to be?
OpenStudy (bananas1234):
the answer
OpenStudy (unklerhaukus):
its not right
OpenStudy (bananas1234):
ok
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OpenStudy (unklerhaukus):
factor the numerator and denominator of \(\dfrac{d^2-1}{d^2-d}\)
OpenStudy (bananas1234):
wouldn't the top be the same and the bottom be d^2?
OpenStudy (bananas1234):
@UnkleRhaukus
OpenStudy (unklerhaukus):
nope
OpenStudy (bananas1234):
hmmm well then i am not sure :/ @UnkleRhaukus
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OpenStudy (unklerhaukus):
can you factor
d^2 - d ?
OpenStudy (bananas1234):
(d^2 -d) (d^2 + d)
OpenStudy (unklerhaukus):
d^2 - d = d*d - d
= d(d-1)
OpenStudy (bananas1234):
oh
OpenStudy (unklerhaukus):
d^2-1 = (d-1)(d+1)
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OpenStudy (bananas1234):
what do i do next?
OpenStudy (bananas1234):
@UnkleRhaukus
OpenStudy (unklerhaukus):
\[\frac{d^2-1}{d^2-d}\div\frac{d-1}d\\
=\frac{d^2-1}{d^2-d}\times\frac d{d-1}\\
=\frac{(d-1)(d+1)}{d(d-1)}\times\frac{d}{d-1}\\
=\]
OpenStudy (bananas1234):
d + 1 / d - 1?
OpenStudy (unklerhaukus):
yep
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OpenStudy (bananas1234):
Thank you
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