what is the solution of the system? Y=-8x-2 and Y=-6x+4 (-3,22) (-8/3,1/22) (-14/3,6/22) (3/14,-6/14) will give medal for correct answer
Use susbstituion :) plug equation 1 into equation 2
\[\huge -6x+4=-8x-2\]
you can either solve the system or plug in the given values to see if they fit eg for first one y = 22 -8x - 2 = -8(-3) - 2 = 24 - 2 = 22 they both come to same value so thay fit for first equation Now try the same values for y = -6x + 4 and see if they fit
i think its a
r u sure ?
be confident
im not sure
what does -6(-3) + 4 work out to?
22
so?
it is a
right
thank you
could you help me with this one how many solutions does the system have ? 12y=-3x+20 y=-1/4x+5/3
yw pooja195 's method was quicker than mine though as both -6x+4 and -8x - 2 are equal to y they are equal to each other so you only needed to plug x = 3 into his equation to see if LHS = RHS
the way to do these is to multiply one equation by a number so that the terms in y or x have the same coefficient ( the coefficient is the number in front of the x or y)
so as we have 12y in equation 1 and y in equation 2 we multiply the second one by 12 equation 1 12y = - 3x + 20 equation 2 12y = -3x + 20 - the same equation so how many solution s does this have?
1
No - Hint; you can put any value of x into the equation and work out a value of y - in fact many many values of x...
so theres not just 1 value theres ?
infinte
right infinite solutions
thank you so much
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