Currently have the first 3 answers here to start us off, not sure where to go from here, please help! (problems: http://imgur.com/Eo8fZIR,mJ2vS04,3ys9vme,xyjbOve ) here's what i've got: * A=40 * B=20 * C=12 hour period
What exactly is the question?
There's multiple questions, would you like me to type them out for you? I don't mind.
Are there more than the 3 in the link? Or are you just asking if those answers are correct?
There are more than 3, I have the first 3 which I listed and I need assistance with the rest, I believe the answers for the first 3 that I got are vital to answering the rest.
There are 5 more questions, 2 bonus questions but i'm not too worried about them.
ok. I didn't see the links to the other questions before
Oh it's alright, you've got it or do I need to type them?
I see them.
For part d, a is the amplitude and b is 2π divided by the period The y = cos x parent function has a maximum on the y-axis. Your function has the minimum there, so make "a" negative
so for A, the amplitude was either 40 or 20 from the previous questions, correct?
The amplitude is 20, the answer from B
I didn't have my work pulled up sorry about that, so it's y=20 cos 2pi x?
Wait! I read you wrong, a=20 and b=2pi/the period?
close. you need to divide 2π by the period of 12 and make the amplitude negative to account for the reflection \[y=-20\cos \frac{ 2\pi }{ 12 }x\]
Am I going to need to get this down to one number for the answer to "a=" or will it be an equation?
Or will this be for both a= and b=
oh you're right. They are asking for a and b separately
so a will be -20 and b will be π/6
Does that make sense?
That does, I was wondering when the negative 20 would come in as I looked around online and saw that it would turn out like that, now the next question is to "sketch" and label a graph, Seeing as we can't really do that here, what would I put into my graphing calculator to figure this out?
Not sure if the draw option is any use, im new here
ok
so you want to enter the equation we found above. and set your window to show 1 period at least
so your horizontal axis should be from 0 to 12. and vertical from -20 to 20
y=-20 cos 2pi/12x is the equation I want to put in?
Reduce the 2π/12 to π/6 and use parentheses to avoid ambiguity y=-20 cos (pi/6)x
Hold up, put everything after cos in (). y=-20 cos ((pi/6)x)
Yes
If I add the extra parenthesis it makes two lines, like this: http://imgur.com/KM6VOZB
Is that what we want?
yes. If you zoom out you'll see the waves
Yes! alright so that's all that was? we're done graphing?
yes.
Mind sticking around and helping with the rest? I'll give you medals or whatever the currency on here is.
oh yeah. I just meant we were done with that question
Alright so F, how do we find the average water levels?
Just the top of the waves?
It's the average of the maximum and minimum, which I think was 32 and 12. I need to go back to the beginning to check
52 and 12 I believe
you're right
So what can we do with those to find the average? Divide?
Add them and then divide (52+12)/2 = 22
Crazy how complicated they make it sound and then it's that easy! This next one may be a bit of a challenge
I have the graph on hand, how do I determine where the times are?
That's where the first column comes in. 11:15 is 2 hours after 9:15, so you want to find y when x = 2.
will finding y give the water level?
correct!
not sure how to find it with just x, walk me through it?
yes. It might actually be easier to do this on a calculator than to use the graph. For the first one, plug in 2 for x. y = -20 cos ((π/6)*2) http://www.wolframalpha.com/input/?i=-20+cos+%28%28%CF%80%2F6%29*x%29+at+x+%3D+2
so for each one we just plug in the hours and we get the level, for this it's -10?
right
3:45pm is 7 hours, right?
6.5 hrs
19.31?
yes
and then 6:15 is 9 hours? I'm in high school I should really be able to tell time at this point but it's hard without a clock to look at.
lol. It is 9. I'm just as pathetic. I have to count it on my fingers
wolfram just gave me the answer as "true", that cant be right
copy your link here
Just take out the y= so it will evaluate the expression
0?
yep
for the next one it's looking like we're working backwards, it gives us the water level but not the time, how do we manage this?
Use 7 for y and solve for x. 7 = -20 cos ((π/6)*x)
8.5 hours?
or 7.5
http://www.wolframalpha.com/input/?i=7+%3D+-20+cos+%28%28%CF%80%2F6%29*x%29%2C+0%3Cx%3C12
sorry about that. You have to restrict the domain to just the period, or it will give all possilbe answers
this is looking like jibberish to me, is it 12? i'm seeing 12 a lot in there
hold up. can we go back to part c for a second?
the 12 hour period, yes
The period is actually 24. (9:15 to 3:15 is only half the period)
9:15 to 3:15 is a six hour gap. so six hours from low to high plus 6 hours from high back to low is a 12 hour period, right?
ok. yes. massive brain fart
so is H a 12 hour period as well?
yes, so there will be two solutions over the 12 hour period
Ignore all the "alternate form" gibberish and scroll down to where it says "solutions" You may have to click on the "approximate form" box http://www.wolframalpha.com/input/?i=7+%3D+-20+cos+%28%28%CF%80%2F6%29*x%29%2C+0%3Cx%3C12
Do you see x = 8.32 and x = 3.68?
I see them now yep, what do they have to do with it?
that equals 12?
no, they are the x values where the water level is 7
and they helped us determine that it's a 12 hour period in some way I guess?
The other way around. The equation 7 = -20 cos ((π/6)*x) has infinitely many solutions. We used the 12 hour period to restrict the amount of solutions the equation would give us. That's why the 0<x<12 is in there
got it!
So to find the times for H, add 3.68 hrs and 8.32 hrs to 9:15.
20.115
not sure how to add .___ in time
9:15 is 9.25 hours 9.25 hrs + 3.68 hrs = 12.93 hr (pm) convert 0.93 hrs to minutes by multiplying by 60 → 55.8 minutes First time 12:56 pm
wait a minute are we still on H or have we moved onto the bonus questions? I'm getting lost in all these times here as I know 9am is involved in both
I thought we were still on H
No this is still H
I was showing you how to add the times.
The first time we got for H was 3.68 hours. We need to add that to 9:15 to get the time of day the question is asking for
that makes much more sense, and when you did that you got 12.93, correct? should we round this?
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