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Algebra 22 Online
OpenStudy (anonymous):

Currently have the first 3 answers here to start us off, not sure where to go from here, please help! (problems: http://imgur.com/Eo8fZIR,mJ2vS04,3ys9vme,xyjbOve ) here's what i've got: * A=40 * B=20 * C=12 hour period

OpenStudy (anonymous):

What exactly is the question?

OpenStudy (anonymous):

There's multiple questions, would you like me to type them out for you? I don't mind.

OpenStudy (anonymous):

Are there more than the 3 in the link? Or are you just asking if those answers are correct?

OpenStudy (anonymous):

There are more than 3, I have the first 3 which I listed and I need assistance with the rest, I believe the answers for the first 3 that I got are vital to answering the rest.

OpenStudy (anonymous):

There are 5 more questions, 2 bonus questions but i'm not too worried about them.

OpenStudy (anonymous):

ok. I didn't see the links to the other questions before

OpenStudy (anonymous):

Oh it's alright, you've got it or do I need to type them?

OpenStudy (anonymous):

I see them.

OpenStudy (anonymous):

For part d, a is the amplitude and b is 2π divided by the period The y = cos x parent function has a maximum on the y-axis. Your function has the minimum there, so make "a" negative

OpenStudy (anonymous):

so for A, the amplitude was either 40 or 20 from the previous questions, correct?

OpenStudy (anonymous):

The amplitude is 20, the answer from B

OpenStudy (anonymous):

I didn't have my work pulled up sorry about that, so it's y=20 cos 2pi x?

OpenStudy (anonymous):

Wait! I read you wrong, a=20 and b=2pi/the period?

OpenStudy (anonymous):

close. you need to divide 2π by the period of 12 and make the amplitude negative to account for the reflection \[y=-20\cos \frac{ 2\pi }{ 12 }x\]

OpenStudy (anonymous):

Am I going to need to get this down to one number for the answer to "a=" or will it be an equation?

OpenStudy (anonymous):

Or will this be for both a= and b=

OpenStudy (anonymous):

oh you're right. They are asking for a and b separately

OpenStudy (anonymous):

so a will be -20 and b will be π/6

OpenStudy (anonymous):

Does that make sense?

OpenStudy (anonymous):

That does, I was wondering when the negative 20 would come in as I looked around online and saw that it would turn out like that, now the next question is to "sketch" and label a graph, Seeing as we can't really do that here, what would I put into my graphing calculator to figure this out?

OpenStudy (anonymous):

Not sure if the draw option is any use, im new here

OpenStudy (anonymous):

We could use this: https://www.desmos.com/calculator

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so you want to enter the equation we found above. and set your window to show 1 period at least

OpenStudy (anonymous):

so your horizontal axis should be from 0 to 12. and vertical from -20 to 20

OpenStudy (anonymous):

y=-20 cos 2pi/12x is the equation I want to put in?

OpenStudy (anonymous):

Reduce the 2π/12 to π/6 and use parentheses to avoid ambiguity y=-20 cos (pi/6)x

OpenStudy (anonymous):

Hold up, put everything after cos in (). y=-20 cos ((pi/6)x)

OpenStudy (anonymous):

Have this so far, should I fix it with the ()'s? http://imgur.com/ptftpkN

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

If I add the extra parenthesis it makes two lines, like this: http://imgur.com/KM6VOZB

OpenStudy (anonymous):

Is that what we want?

OpenStudy (anonymous):

yes. If you zoom out you'll see the waves

OpenStudy (anonymous):

Yes! alright so that's all that was? we're done graphing?

OpenStudy (anonymous):

yes.

OpenStudy (anonymous):

Mind sticking around and helping with the rest? I'll give you medals or whatever the currency on here is.

OpenStudy (anonymous):

oh yeah. I just meant we were done with that question

OpenStudy (anonymous):

Alright so F, how do we find the average water levels?

OpenStudy (anonymous):

Just the top of the waves?

OpenStudy (anonymous):

It's the average of the maximum and minimum, which I think was 32 and 12. I need to go back to the beginning to check

OpenStudy (anonymous):

52 and 12 I believe

OpenStudy (anonymous):

you're right

OpenStudy (anonymous):

So what can we do with those to find the average? Divide?

OpenStudy (anonymous):

Add them and then divide (52+12)/2 = 22

OpenStudy (anonymous):

Crazy how complicated they make it sound and then it's that easy! This next one may be a bit of a challenge

OpenStudy (anonymous):

I have the graph on hand, how do I determine where the times are?

OpenStudy (anonymous):

That's where the first column comes in. 11:15 is 2 hours after 9:15, so you want to find y when x = 2.

OpenStudy (anonymous):

will finding y give the water level?

OpenStudy (anonymous):

correct!

OpenStudy (anonymous):

not sure how to find it with just x, walk me through it?

OpenStudy (anonymous):

yes. It might actually be easier to do this on a calculator than to use the graph. For the first one, plug in 2 for x. y = -20 cos ((π/6)*2) http://www.wolframalpha.com/input/?i=-20+cos+%28%28%CF%80%2F6%29*x%29+at+x+%3D+2

OpenStudy (anonymous):

so for each one we just plug in the hours and we get the level, for this it's -10?

OpenStudy (anonymous):

right

OpenStudy (anonymous):

3:45pm is 7 hours, right?

OpenStudy (anonymous):

6.5 hrs

OpenStudy (anonymous):

19.31?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

and then 6:15 is 9 hours? I'm in high school I should really be able to tell time at this point but it's hard without a clock to look at.

OpenStudy (anonymous):

lol. It is 9. I'm just as pathetic. I have to count it on my fingers

OpenStudy (anonymous):

wolfram just gave me the answer as "true", that cant be right

OpenStudy (anonymous):

copy your link here

OpenStudy (anonymous):

Just take out the y= so it will evaluate the expression

OpenStudy (anonymous):

0?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

for the next one it's looking like we're working backwards, it gives us the water level but not the time, how do we manage this?

OpenStudy (anonymous):

Use 7 for y and solve for x. 7 = -20 cos ((π/6)*x)

OpenStudy (anonymous):

8.5 hours?

OpenStudy (anonymous):

or 7.5

OpenStudy (anonymous):

sorry about that. You have to restrict the domain to just the period, or it will give all possilbe answers

OpenStudy (anonymous):

this is looking like jibberish to me, is it 12? i'm seeing 12 a lot in there

OpenStudy (anonymous):

hold up. can we go back to part c for a second?

OpenStudy (anonymous):

the 12 hour period, yes

OpenStudy (anonymous):

The period is actually 24. (9:15 to 3:15 is only half the period)

OpenStudy (anonymous):

9:15 to 3:15 is a six hour gap. so six hours from low to high plus 6 hours from high back to low is a 12 hour period, right?

OpenStudy (anonymous):

ok. yes. massive brain fart

OpenStudy (anonymous):

so is H a 12 hour period as well?

OpenStudy (anonymous):

yes, so there will be two solutions over the 12 hour period

OpenStudy (anonymous):

Ignore all the "alternate form" gibberish and scroll down to where it says "solutions" You may have to click on the "approximate form" box http://www.wolframalpha.com/input/?i=7+%3D+-20+cos+%28%28%CF%80%2F6%29*x%29%2C+0%3Cx%3C12

OpenStudy (anonymous):

Do you see x = 8.32 and x = 3.68?

OpenStudy (anonymous):

I see them now yep, what do they have to do with it?

OpenStudy (anonymous):

that equals 12?

OpenStudy (anonymous):

no, they are the x values where the water level is 7

OpenStudy (anonymous):

and they helped us determine that it's a 12 hour period in some way I guess?

OpenStudy (anonymous):

The other way around. The equation 7 = -20 cos ((π/6)*x) has infinitely many solutions. We used the 12 hour period to restrict the amount of solutions the equation would give us. That's why the 0<x<12 is in there

OpenStudy (anonymous):

got it!

OpenStudy (anonymous):

So to find the times for H, add 3.68 hrs and 8.32 hrs to 9:15.

OpenStudy (anonymous):

20.115

OpenStudy (anonymous):

not sure how to add .___ in time

OpenStudy (anonymous):

9:15 is 9.25 hours 9.25 hrs + 3.68 hrs = 12.93 hr (pm) convert 0.93 hrs to minutes by multiplying by 60 → 55.8 minutes First time 12:56 pm

OpenStudy (anonymous):

wait a minute are we still on H or have we moved onto the bonus questions? I'm getting lost in all these times here as I know 9am is involved in both

OpenStudy (anonymous):

I thought we were still on H

OpenStudy (anonymous):

No this is still H

OpenStudy (anonymous):

I was showing you how to add the times.

OpenStudy (anonymous):

The first time we got for H was 3.68 hours. We need to add that to 9:15 to get the time of day the question is asking for

OpenStudy (anonymous):

that makes much more sense, and when you did that you got 12.93, correct? should we round this?

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