Devon and his friends bought strawberry wafers for $3 per packet and chocolate wafers for $1 per packet at a carnival. They spent a total of $30 to buy a total of 22 packets of wafers of the two varieties.
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OpenStudy (ccchristian1):
Part A: Write a system of equations that can be solved to find the number of packets of strawberry wafers and the number of packets of chocolate wafers that Devon and his friends bought at the carnival. Define the variables used in the equations. (5 points)
Part B: How many packets of chocolate wafers and strawberry wafers did they buy? Explain how you got the answer and why you selected a particular method to get the answer. (5 points)
OpenStudy (ccchristian1):
@UsukiDoll
OpenStudy (anonymous):
hello
OpenStudy (ccchristian1):
yeah?
OpenStudy (anonymous):
lets make strawberry x and chocolate y
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OpenStudy (usukidoll):
oh gawd I hate these word problems sorry ^^'
OpenStudy (ccchristian1):
@UsukiDoll you got time ? lol
OpenStudy (ccchristian1):
oh alright its okay lol @UsukiDoll
OpenStudy (anonymous):
strawberry is 3 dollars so 3x
chocolate is 1 dollar so 1y
OpenStudy (anonymous):
3x+y=30
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OpenStudy (anonymous):
That's the first equation
OpenStudy (ccchristian1):
thats for part a?^
OpenStudy (anonymous):
the second equation is
x+y=22
OpenStudy (anonymous):
both equations are part of the 'system of equations'
OpenStudy (anonymous):
For part B we need to solve for x and y.
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OpenStudy (anonymous):
are you familiar with substitution?
OpenStudy (ccchristian1):
not really
OpenStudy (anonymous):
ok, so we have our two equations
3x+y=30 and
x+y=22
OpenStudy (anonymous):
isolate x or y in one of the equations and then plug it into the other equation
OpenStudy (anonymous):
so isolate x in the second equation
x+y=22
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OpenStudy (ccchristian1):
3x+y=22?
OpenStudy (anonymous):
nope, we're just looking at x+y=22 right now
OpenStudy (anonymous):
so get x by itself
OpenStudy (ccchristian1):
so what will it be?
OpenStudy (anonymous):
we have to subtract y from both sides
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OpenStudy (anonymous):
this gives x=22-y
OpenStudy (anonymous):
now we take 22-y and replace that with x in the other equation
OpenStudy (anonymous):
3(22-y)+y=30
OpenStudy (anonymous):
solve for y
OpenStudy (ccchristian1):
this will tell us how much packets did they buy
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OpenStudy (anonymous):
ya
OpenStudy (ccchristian1):
then whats next ?
OpenStudy (ccchristian1):
after that
OpenStudy (anonymous):
y will tell us how many chocolate was bought.
what did you get for y
OpenStudy (ccchristian1):
33?
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OpenStudy (anonymous):
nope, you have to solve the equation
OpenStudy (anonymous):
first foil out 3(22-y)
OpenStudy (ccchristian1):
19?
OpenStudy (anonymous):
where are you getting these numbers?
OpenStudy (ccchristian1):
18?
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OpenStudy (anonymous):
that's right, good job
OpenStudy (ccchristian1):
yeeeeeeee les get it
OpenStudy (anonymous):
so we know there are 18 chocolate wafers. how many strawberry are there?
OpenStudy (anonymous):
substitute it back into this equation
x+y=22
OpenStudy (ccchristian1):
to what number ??
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OpenStudy (anonymous):
well we just found that y was 18
OpenStudy (ccchristian1):
soooo......
OpenStudy (ccchristian1):
so 22?
OpenStudy (anonymous):
x+y=22
If y is 18, what is x
OpenStudy (ccchristian1):
22?
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OpenStudy (anonymous):
x+(18)=22
OpenStudy (anonymous):
solve for x
OpenStudy (ccchristian1):
4?
OpenStudy (anonymous):
correct
so there are 4 strawberry and 18 chocolate
OpenStudy (anonymous):
4 x 3 + 18 x 1 = 30
18 + 4 = 22
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OpenStudy (anonymous):
This method is called the substitution method where you substitute one equation in for another