Question

how do find the vertex and foci of this hyperbola
(x-2)^2/36 - (y+1)^2/64 =1

Answer 1

you can simply guess the vertex of the hyperbola has (2,-1)
the focii is (+ae,0) , (-ae,0)
you can find e by b^2 = a^2(e^2-1)
and just shift the vertex wrt the vertex

Answer 2

Okay let me try that and see what I get

Answer 3

sure :)

Answer 4

wait so I plugged into my calculator "8=6(e^2-1)
I got 16.3096

Answer 5

I feel like I did something wrong

Answer 6

dear a^2 =36 and b^2 = 64
you plugged a and b instead of a^2 and b^2

Answer 7

oh wow thanks

Answer 8

let me redo that using a^2 and b^2

Answer 9

now I get 97