Question

http://prntscr.com/7brctg EASY QUESTION. QUICK MEDAL.

Answer 1

531438 i think.

Answer 2

\[(3^6)^2\] Multiply the numbers 6x2

Answer 3

When theres exponentials and the numbers are multiplying, add.

Answer 4

so 3^12 x 3^0 (Just add the exponents)

Answer 5

you guys forgot to mention that whenever the exponent is 0 the ending result is a 1?
\[3^0 = 1\]

and as for \[(3^6)^2\] you can either multiply the 2 with the 6 making it \[6 \times 2 = 12\]

or you can write \[(3^6)\] two times. the outer exponent tells you how many times to write and using exponential laws like \[a^3a^3 \rightarrow a^{3+3} \rightarrow a^6\]

so in this case for \[(3^6)(3^6) \rightarrow 3^{6+6} \rightarrow 3^{12}\]

\[3^{12} \cdot 3^0\] Since \[3^0 = 1\]

\[3^{12} \cdot 1 \rightarrow 3^{12} \]

Answer 6

\[(3^6)^2\cdot3^0=3^{6\times2+0}\]

Answer 7

that's still 3^12 regardless of what you're doing... as long as none of the math laws are being broken, more than one method to solving this problem exists. This issue lead to a lot of debate between me and my Mathematical Biology professor last semester.

Answer 8

and again there's the zero exponent special case... why not use that first and then use exponential laws on ((3^6))^2

Answer 9

yay medal :)

Answer 10

biologist will tell you that multiplication and division are that same thing

Answer 11

D:

Answer 12

boooooooooo! Taking the special zero exponent case would've been easier.