Solve by using the perfect squares method.

x2 + 16x + 64= 0

Question

Solve by using the perfect squares method. 
 
x2 + 16x + 64= 0

anonymous · Answer

@mathmate

pooja195 · Answer

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pooja195 · Answer

$$\huge x^2 + \sqrt{16x}+ \sqrt{64}= 0$$

anonymous · Answer

what is that

pooja195 · Answer

we square root the perfect squares

mathmate · Answer

@pooja195 
We squareroot the first and last terms.
$\sqrt{x^2}=x$ and $\sqrt{64}=8$

mathmate · Answer

So far so good, the first and last terms are perfect squares.
Next:

mathmate · Answer

we double the product, 2(8x)=16x
If this equals the absolute value of the middle term |16x|, we have a perfect square expression.
The sign between x and 8 is determined by the sign of the middle term.

mathmate · Answer

So 
$x^2 + 16x + 64= (x+8)^2$, or
$(x+8)^2=0$

mathmate · Answer

@Nitaoffaith 
I'll let you take it from here to finish solving the equation.

anonymous · Answer

ok thx

mathmate · Answer

You're welcome!  :)