Question

How much heat is required to vaporize 1.5 kg of liquid water at its boiling point (delta Hv = 2.26 × 10^6 J/kg)?
A. 6.6 * 10^-7 J
B. -1.5 * 10^6 J
C. 1.5 * 10^6 J
D. 3.4 * 10^6 J

Answer 1

here we have to multiply the hentalpy change Hv, by the mass of the object

Answer 2

so 2.26*10^6 *1.5? and we get 3390000 and so our answer is choice D?

Answer 3

oops.. enthalpy*

Answer 4

yes! correct!

Answer 5

yay!! thank you!!

Answer 6

:)