Question

what is the change of entropy for a heat engine using 500.0 J at 20.0°C ?

0.04 J/K , 0.25 J/K , 0.59 J/K , or 1.71 J/K

? :/

Answer 1

it is simple, we have to apply this formula:
\[S = \frac{{\Delta Q}}{T}\]

Answer 2

okay! 500/20 ? = 25? so our solution would be 0.25 J/K ?

Answer 3

no, we have to compute the absolute temperature first:
T =20+273=293 °K

Answer 4

ohh okay! so 500/293 = 1.706? so our solution is 1.71 J/K ?

Answer 5

yes! that's right!

Answer 6

yay! thank you!!

Answer 7

:)