Fan and Medal! The following function represents the profit P(n), in dollars, that a concert promoter makes by selling tickets for n dollars each: P(n) = -250n^2 + 2,500n - 4,000 Part A: What are the zeroes of the above function, and what do they represent? Show your work. (4 points) Part B: Find the maximum profit by completing the square of the function P(n). Show the steps of your work. (4 points) Part C: What is the axis of symmetry of the function P(n)? (2 points)
\[P(n) = -250n^2 + 2,500n - 4,000 \] you want the zeros?
I already finished part A I know the 0's are 2 and 8
no that is wrong
\(n\) is the price i guess if he prices the tickets at $2 or at $8 he makes no money
The zeroes of the function would be 2 and 8. The zeroes of the function above represents the specific prices, 2 and 8, which will result in a zero profit.
is that correct?
yes looks good to me
Okay (:
Now how do I "complete the square"
there is a much easier way to do it (find the max) than completing the square, but we can do it that way too if you have to
first of all it is pretty obvious that if it is zero at 2 and at 8 then it is the biggest half way between at 5
plus the first coordinate of the vertex is always \[-\frac{b}{2a}\] which in your case is \[-\frac{2500}{2\times (-250)}=5\]
Yeah, but it specifically asks to complete the square (which I hate because it's so confusing)
but we can still complete the square if you are dying to do it
factor out the \(-250\) from the first two terms
\[ -250n^2 + 2,500n - 4,000 \] \[-250(n^2-10n)-4,000\]
P(n)=-250(n^2-10n)-4000?
Okay i got that aha
right that is step one
then half of \(-10\) is \(-5\) complete the square via \[-250(n-5)^2-4000+25\times 250\]
Yeah... I got lost there ):
yeah i can see why
when you replace \(n^2-10n\) by \(n-5)^2\) you have changed it
\[(n-5)^2=n^2-10n+25\] so you have added \(25\) when you make the change
Ohh, okay I see that now, but like if it's so many numbers and such, my brain likes to just stop reading it
why 25 though?
because when you square \(n-5\) you get \((n-5)^2=n^2-10n+25\)
Ohhh
Okay (:
now don't forget the \(-250\) outside the parentheses
so actually you have subtracted \(25\times 250\) so you have to add it back
hence \[-250(n-5)^2-4000+25\times 250\]
but why the times symbol?
what else would you like me to write? look at this line \[-250(n-5)^2\]
if you multiply that out you get \[-250(n^2-10n+25)\] as a first step
I meant the times symbol for 25 x 250
and when you multiply that out, you get \[-250n^2+2500n-6250\]
you subtracted \(6250\) from the original expression, so you have to add it back
there is really a much much easier way to do it
Yeah, but my algebra teachers just love making us suffer haha
since you know that the first coordinate of the vertex is \(5\) if you want the second coordinate, all you have to do is find \(P(5)\)
you can pretend to to it the other way, but then just find \(P(5)\) and write that out at the end
so after P(n)=-250(n-5)^2-4000+25*250 ,what do I do, or is that the final step?
algebra teachers lead sad lives, most are either frustrated mathematicians or are teaching at the outer edge of their knowledge
compute the number at the end
-250(n-5)^2-4000+6250
\[-400+25\times 250=2250\]
-250(n-5)^2+2250
yes
And now? do I make it (n-5)(n-5)?
@perl
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