Question

question answered

Answer 1

Have you graphed them?

Answer 2

The 6 in the second graphs "pushes" the graph upwards. the 5 in 5/x reduces the "steepness" of the graph of 1/x.

Does that make sense?

This might help -

http://www.wolframalpha.com/input/?i=plot+y%3D1%2Fx+%2Cy%3D5%2Fx%2B6

Look what happens in an extreme case when instead of 5/x we use 50/x -

http://www.wolframalpha.com/input/?i=plot+y%3D1%2Fx+%2Cy%3D50%2Fx%2B6

The slope of 1/x looks almost like a "corner" now.

Answer 3

sorry about that, went afk, the question doesn't have them nor ask for them to be graphed

Answer 4

should I?

Answer 5

I suppose I need to

Answer 6

It's ALWAYS a good practice to do that. You will gain much more insight, even if the question is not asked.

Answer 7

looking at them from your link, what's the difference i'm supposed to be seeing?

Answer 8

You see that the one with the 1/x term is much more like a "corner" than the 5/x term. When we use something like 50/x instead of 5/x, you see this effect even better. When you add a constant to an equation, it's like putting it on a ladder -- it lifts up the equation.

Answer 9

I got a 2/3 on this question for saying "These graphs combare by 5/x stretching out the graph five times more and the 6 makes it reach 6 unites higher while the other equation only stretches by 1 and nothing more." what did I do wrong?

Answer 10

sorry to cut you off there, I see what you mean

Answer 11

I also said combare instead of compare

Answer 12

any input?

Answer 13

The graph y = 5/x + 6 has a smaller slope and is offset upward by 6 units compared to the y=1/x

Answer 14

medal and fanned :)

Answer 15

Hopefully this makes sense