Mathematics
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OpenStudy (anonymous):
PLEASE HELP! WILL MEDAL! Find the sum of the series.
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OpenStudy (anonymous):
\[\sum_{n=1}^{15} (2n+1)\]
OpenStudy (anonymous):
there are a couple ways to do this
OpenStudy (anonymous):
Okay I need the simplest way because I'm not good with this.
OpenStudy (anonymous):
ok lets find the first term, which means replace \(n\) by \(1\)
what do you get?
OpenStudy (anonymous):
3?
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OpenStudy (anonymous):
if that is confusing too, let me know and i will show you
lol no not "3?" just "3"
OpenStudy (anonymous):
I know it is just 3 I was asking if 3 was right.
OpenStudy (anonymous):
yeah \(2\times 1+1=3\)
ok now the top number is 15 so lets find the 15th term
replace \(n\) by \(15\) and see what you get
OpenStudy (anonymous):
31
OpenStudy (anonymous):
ok good
now there are 15 terms all together
one formula you can use is
\[\huge \frac{n}{2}\left(a_1+a_n\right )\]
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OpenStudy (anonymous):
you computed \(a_1=3,a_{15}=31\) and in this case \(n=15\)
OpenStudy (anonymous):
so do this
\[\frac{15}{2}(3+31)\]
OpenStudy (anonymous):
15/2(33)
OpenStudy (anonymous):
add first, divide by 2 then multiply by 15
OpenStudy (anonymous):
you got that?
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OpenStudy (anonymous):
I meant 34 my number buttons are acting up and no. I was just stating the equation.
OpenStudy (anonymous):
ok so now divide 34 by 2
then multiply the result by 15
OpenStudy (anonymous):
255
OpenStudy (anonymous):
you found the sount
OpenStudy (anonymous):
sound
bingo
yes
good work
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OpenStudy (anonymous):
Thank you for your help!
OpenStudy (anonymous):
yw