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Mathematics 16 Online
OpenStudy (anonymous):

PLEASE HELP! WILL MEDAL! Find the sum of the series.

OpenStudy (anonymous):

\[\sum_{n=1}^{15} (2n+1)\]

OpenStudy (anonymous):

there are a couple ways to do this

OpenStudy (anonymous):

Okay I need the simplest way because I'm not good with this.

OpenStudy (anonymous):

ok lets find the first term, which means replace \(n\) by \(1\) what do you get?

OpenStudy (anonymous):

3?

OpenStudy (anonymous):

if that is confusing too, let me know and i will show you lol no not "3?" just "3"

OpenStudy (anonymous):

I know it is just 3 I was asking if 3 was right.

OpenStudy (anonymous):

yeah \(2\times 1+1=3\) ok now the top number is 15 so lets find the 15th term replace \(n\) by \(15\) and see what you get

OpenStudy (anonymous):

31

OpenStudy (anonymous):

ok good now there are 15 terms all together one formula you can use is \[\huge \frac{n}{2}\left(a_1+a_n\right )\]

OpenStudy (anonymous):

you computed \(a_1=3,a_{15}=31\) and in this case \(n=15\)

OpenStudy (anonymous):

so do this \[\frac{15}{2}(3+31)\]

OpenStudy (anonymous):

15/2(33)

OpenStudy (anonymous):

add first, divide by 2 then multiply by 15

OpenStudy (anonymous):

you got that?

OpenStudy (anonymous):

I meant 34 my number buttons are acting up and no. I was just stating the equation.

OpenStudy (anonymous):

ok so now divide 34 by 2 then multiply the result by 15

OpenStudy (anonymous):

255

OpenStudy (anonymous):

you found the sount

OpenStudy (anonymous):

sound bingo yes good work

OpenStudy (anonymous):

Thank you for your help!

OpenStudy (anonymous):

yw

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