Just need someone to check my answer. One problem only.

3. A 5.0 µC point charge is moved within an electric field and has an electric potential energy change of 10.0 J. What is the electric potential difference before and after the charge was moved? Show your work. (µC = 1.0 × 10–6 C)

The potential difference * charge = potential energy change of charge

delta V = 10J/(5*10^-6) = 2*10^6 volts

Question

Just need someone to check my answer. One problem only.





3.	A 5.0 µC point charge is moved within an electric field and has an electric potential energy change of 10.0 J. What is the electric potential difference before and after the charge was moved? Show your work. (µC = 1.0 × 10–6 C)


The potential difference * charge = potential energy change of charge 

delta V = 10J/(5*10^-6) = 2*10^6 volts

anonymous · Answer

@Thesmarterone help?

anonymous · Answer

you have the formula on it
$\triangle U= \dfrac{1}{2}CV^2$ so that you can calculate the V from it, just plug in the numbers. Don't forget convert the unit.

anonymous · Answer

oh ok thnx @Thesmarterone can i tag you for physics questions in the future?