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Mathematics 20 Online
OpenStudy (anonymous):

Find the standard form of the equation of the parabola with a focus at (0, -2) and a directrix at y = 2.

OpenStudy (anonymous):

lol no one likes these conic section problems, do they?

OpenStudy (anonymous):

but it is real real easy

OpenStudy (anonymous):

do you now what the parabola looks like? if so, we can do it in like 15 seconds

OpenStudy (anonymous):

Yes. I think so.

OpenStudy (anonymous):

open up, down, left or right?

OpenStudy (anonymous):

|dw:1433210682010:dw|

OpenStudy (anonymous):

Opens down?

OpenStudy (anonymous):

I'm not so sure now.

OpenStudy (anonymous):

yes it iopens down

OpenStudy (anonymous):

and the vertex is exactly half way between the focus and the directrix

OpenStudy (anonymous):

so it is evidently at \((0,0)\) making your equation look like \[4py=x^2\]

OpenStudy (anonymous):

all you need is \(p\) which is the distance between the focus and the vertex (or the vertex and the directrix) which is clearly 2 final answer \[-8y=x^2\]

OpenStudy (anonymous):

Thanks!

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