Question

Please Help!! Medal!
If tanX=3/4 , what is sin X??

Answer 1

you need the pythagorean theorem a^2+b^2 =c^2

so for tan x = 3/4 that's tan x = opposite / adjacent

Answer 2

so we need to solve for c
3^2+4^2 =c^2
9+16 =c^2
25=c^2
5 = c

normally the answer would be 5 and -5 , but we can't have negative signs at all for geometric shapes.

Answer 3

Imma eat lunch

Answer 4

UsukiDoll
The angle 'x' would be located in the lower left corner of the triangle.

Answer 5

sine (x) = opposite / hypotenuse
sine (x) = 3 / c

Answer 6

So that would be 4/3??

Answer 7

No
sine (x) = 3 / c
What is 'c'?

Answer 8

it's asking for the sin x version
we are given that tan x = 3/4
tan x is usually opposite/adjacent
cos x is adjacent/hypotenuse
sin x is opposite / hypotenuse

your hypotenuse value is missing!

Answer 9

if the opposite -> 3
adjacent -> 4

our sin x is 3/ ?
that ? is our unknown and we need the Pythagorean theorem for a^2+b^2=c^2

Answer 10

so using the Pythagorean theorem
a^2+b^2=c^2
let your a = 3 and b = 4
3^2+(4)^2=c^2
9+16=c^2
25=c^2
5 = c

that's your hypotenuse! since Hypotenuse is 5 and makes sense since it's supposed to be the longest side of the triangle
Your sin x is opposite/ hypotenuse which is 3/5

Answer 11

sorry if I sounded a bit arrogant... but.. the reason why it's not 4/3 is because that's the cotangent

so...

sin x = opposite/hypotenuse
cos x = adjacent/hypotenuse
tan x = opposite/adjacent

csc x, sec x, and cot x are backwards versions of what I've typed above

tan x = opposite/adjacent (3/4)
cot x = adjacent/opposite (4/3)