Question

Check please!

Answer 1

@ganeshie8

Answer 2

is that correct? I feel like I did something wrong xD

Answer 3

doesn't look correct

Answer 4

Yeah I figured.

Answer 5

scroll down
http://www.wolframalpha.com/input/?i=focus+20x%5E2%2B4y%5E2%3D5

Answer 6

hrrm but I want to know the process of how to get there ( so i learn it better) :P

Answer 7

(x^2/20)+(y^2/4)=5

Answer 8

a^2=20
a=2sq5

Answer 9

b^2=4
b=2

Answer 10

\[20x^2+4y^2 = 5\]

start by dividing both sides by \(5\)

Answer 11

oooh oh I forgot to get one on the right side

Answer 12

\[\frac{ 20x^2 }{ 5 }+\frac{ 4y^2 }{ 5 }=0\]

Answer 13

\[20x^2+4y^2 = 5\]

dividing both sides by \(5\) gives

\[\frac{20x^2}{5}+\frac{4y^2}{5} = \frac{5}{5}\]

which is same as
\[\frac{x^2}{1/4} + \frac{y^2}{5/4}=1\]

Answer 14

right

Answer 15

\(\frac{5}{5}\) equals \(1\)

not \(0\)

Answer 16

aii yeah.

Answer 17

\[\frac{x^2}{1/4} + \frac{y^2}{5/4}=1\]

\(a^2 = 5/4\)
\(b^2 = 1/4\)

Answer 18

Wouldn't it be 4/5? not 5/4?

Answer 19

No remember an ellipse as following \[\frac{ x^2 }{ a^2 } + \frac{ y^2 }{ b^2 }=1\]

Answer 20

...then it'd be
a^2 = 1/4
b^2 = 5/4
? o.o

Answer 21

which ever is big is \(a\)

Answer 22

oou.

Answer 23

\[a \ge b > 0 \]

Answer 24

big : major : \(a\)
small : minor : \(b\)

Answer 25

Yeah yeah, I gotcha now :)

Answer 26

5/4 is greater than 1/4
so the thing under \(y\) is \(a\) and consequently the ellipse stretches along \(y\) axis (vertical)

Answer 27

yeah

Answer 28

\(a^2 = 5/4\)
\(b^2 = 1/4\)

next use the chart for vertical ellipse

Answer 29

It's best if you graph it, then everything becomes obvious say we have \[\frac{ x^2 }{ 9 }+\frac{ y^2 }{ 5 }=1\] such a bad drawing but notice i square root 9 and 5 \[a^2 = 9 \implies \sqrt{9} = 5~~~~~b^2 = 5 \implies \sqrt{5}\]