Question

Quick Question! Medal and fan

Calculate the discriminant to determine the number of real roots.

y = x2 – 6x + 9.

How many real roots does the equation have?

A.one real root
B.two real roots
C.no real roots
D.no solution to the equation

Answer 1

@dmndlife24 @Ilovecake @Thesmarterone

Answer 2

discriminant=b*b-4*a*c here a=1,b=-6,c=9

Answer 3

if d is positive then then two real roots and zero then two roots are same that is one root which is equal to other.

Answer 4

If the discriminant (\(\Delta\)) is 0, the equation has a single real root (with multiplicity 2).
If the discriminant is > 0, the equation has two real roots. If the discriminant is < 0, the equation has two complex roots.

Remember, the discriminant is the quantity under the square root sign in the equation for the solutions of a quadratic:

\[x =\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Answer 5

hmmm...okay, i think i understand, not very sure though