Question

An electric field measured near a point charge of 3.00 × 10^-6 C has a strength of 6.00 × 10^5 N/C. How far is the point from the source charge?

0.095 m , 0.21 m , 0.36 m , or 0.42 m ?

Answer 1

here we have to apply this formula:
\[\Large E\left( r \right) = K\frac{Q}{{{r^2}}}\]

Answer 2

ok!

Answer 3

what happens next?

Answer 4

so we can write:
\[\Large r = \sqrt {\frac{{KQ}}{E}} = \sqrt {\frac{{9 \times {{10}^9} \times 3 \times {{10}^{ - 6}}}}{{6 \times {{10}^5}}}} \]

Answer 5

ok! so we get this?

0.212? so our solution is 0.21 m ?

Answer 6

yes! correct!

Answer 7

yay! thank you!:)

Answer 8

:)