Question

Two parallel plates have an electric potential difference of 20.0 V. If the electric field between them has a strength of 1.0 × 10^3 N/C, then how far apart are the plates?

1.0 cm , 2.0 cm , 5.0 cm , or 10.0 cm

Answer 1

here we have to apply this formula:
\[\Large \Delta V = Ed\]

Answer 2

ok! what do we plug in?

Answer 3

it is simple, here is the next step:
\[\Large d = \frac{{\Delta V}}{E} = \frac{{20}}{{{{10}^3}}}\]

Answer 4

ok! so we get this?0.02 m ? meaning our solution is 2.0 cm?

Answer 5

that's right!

Answer 6

yay! thanks!!

Answer 7

:)