Question

Which best describes the spread of a set of data that has an interquartile range of 18 and a mean absolute deviation of 10?
A.
The average distance of all data values from the mean is 18 and the middle 50% of data values has a range of 10.
B.
The average distance of all data values from the mean is 14 and the middle 50% of data values has a range of 8.
C.
The average distance of all data values from the mean is 14 and the middle 50% of data values has a range of 28.
D.
The average distance of all data values from the mean is 10 and the middle 50% of data values has a range of 18.

Answer 1

@tkhunny

Answer 2

You still haven't done the other problem.
Please don't post problems with no work shown.

What say you?

Answer 3

what say you? what does that mean?

Answer 4

this is from the other problem. 38 - 19 = 19
27 - 19 = 8
21 - 19 = 2
19 - 16 = 3
19 - 10 = 9
19 - 2 = 17

19 + 8 + 2 + 3 + 9 + 17 = 58

58 / 6 ≈ 9.7

Answer 5

Why in the world would you post that here? So nice to be able to see your work. Very good. Keep that up.

Answer 6

now can you help me on THIS problem and TY

Answer 7

Mean Absolute Deviation = Mean of the Distance from the Mean. It is calculated as 10. Shall we pick 18 or 14? I think not.

Answer 8

you think not what?

Answer 9

@tkhunny

Answer 10

It's a complete sentence, given the context. You have to do some thinking. Go!