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Chemistry 15 Online
OpenStudy (anonymous):

An element has a mass of 9.1229*10^-23 g. Identify the element. I'm not sure where to begin to identify this element.

Vocaloid (vocaloid):

Hm, the question is a bit unclear, but I would guess that 9.1229*10^-23g is the mass of one atom? in that case, multiply the mass of the atom by Avogadro's number (6.022*10^23) to find the mass of one MOLE of that element. Then, look at the periodic table to find which element matches with the element you have here.

OpenStudy (anonymous):

@Vocaloid Yes, it is very unclear that's why I'm so confused. Yes, it is the mass of one of the element's atoms. So, I take \[\left( 9.1229*10^{-23} \right)*(\frac{ 6.022*10^23 }{ 1atm })\] and get the mass of one element to compare to the periodic table?

Vocaloid (vocaloid):

yup! once you multiply those two numbers you will get the mass of one mole

Vocaloid (vocaloid):

so what do you get when you multiply (9.1229*10^-23)*(6.022*10^23)?

OpenStudy (anonymous):

Thank you! I got 54.9381038

Vocaloid (vocaloid):

Yup, so which element is it?

OpenStudy (anonymous):

Manganese.

Vocaloid (vocaloid):

great! you did very well

OpenStudy (anonymous):

Thank you so much for helping me!

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