Question

how do i solve this system of equations
(x+1)^2/25 + (y+2)^2/4 =1
y=(x+1)^2+1
I know that the first one is an ellipse and the second one is a parabola therefore there can be up to 3 intersection points.

Answer 1

ick

Answer 2

i guess you can replace \(y\) in the first equation by \((x+1)^2+1\) but maybe there is an easier way

Answer 3

want to try that? (btw they do not intersect)

Answer 4

its a hard one

Answer 5

the two graphs dont intersect?

Answer 6

no they do not

Answer 7

damn that is wrong

Answer 8

thinking...

Answer 9

ok how about this :\[y=(x+1)^2+1\] so
\[(x+1)^2=y-1\]

Answer 10

replace \((x+1)^2\) in the ellipse with \(y-1\)
you will get a quadratic equation in \(y\)

Answer 11

@iambatman how does that seem to you?

Answer 12

\[\frac{y-1}{25}+\frac{(y+2)^2}{4}=1\]lets try that

Answer 13

\[4(y-1)+25(y+2)^2=100\] thats better

Answer 14

i must be screwing up somehow

Answer 15

omg i got distracted

Answer 16

i am still messing up
i have to figure this out

Answer 17

im really confused with it

Answer 18

me too but i will figure it out somehow

Answer 19

I am just going to graph them both and see what happens

Answer 20

i did that first

Answer 21

http://www.wolframalpha.com/input/?i=%28x%2B1%29^2%2F25+%2B+%28y%2B2%29^2%2F4+%3D1%2C+y%3D%28x%2B1%29^2%2B1

Answer 22

https://www.desmos.com/calculator

Answer 23

Yeah they don't intersect what so ever. Well anyways that is fine. the question just says to graph the system of equations and that's exactly what we both did, thanks:) lol sorry for the confusion.

Answer 24

oooh! it said graph...