Question

X=(3t^2)/2
Y=4t-1
Using these two parametric equations convert it into rectangular form.
Then u have to determine what type of equation the rectangular form describes

I recall don't get this

Answer 1

@satellite73

Do u think u can help?

Answer 2

yes

Answer 3

or better yes, solve
\[y=4t-1\] for \(t\)

Answer 4

you should get \(t=\frac{y-1}{4}\)

Answer 5

Yes

Answer 6

then replace \(t\) in
\[x=\frac{3t^2}{2}\] by \(\frac{y-1}{2}\)

Answer 7

you will have \(x\) written in terms of \(y\)

Answer 8

i get
\[x=\frac{3(y-1)^2}{4}\] check my algebra

Answer 9

Yeah I got that too

Answer 10

well it is wrong 1

Answer 11

it should be
\[x=\frac{3(y-1)^2}{8}\] i forgot to square the 2

Answer 12

Oops I think I did y+2 instead of y-1

Answer 13

oh crap the whole thing is wrong
must be getting late

Answer 14

\[t=\frac{y+1}{4}\]right?

Answer 15

so
\[x=3\frac{\left(\frac{y+1}{4}\right)^2}{2}\]

Answer 16

or
\[x=\frac{3(y+1)^2}{32}\]

Answer 17

Yesss :))

Answer 18

a parabola

Answer 19

Oh so that is rectangular form?

Answer 20

yes

Answer 21

with no parameter of \(t\) is all that means

Answer 22

Okay

Answer 23

Thxx :D