Question

Determine the number of possible triangles, ABC, that can be formed given angle A = 30°, a = 4, and b = 6.
a. 0
b. 1
c. 2

Answer 1

@amoodarya

Answer 2

can you help

Answer 3

one way to solve is : using law of cosine
find "c"
then you can find number of triangle \[b^2+c^2-a^2=2(b)(c) \cos(A)\\36-16+c^2=2(6)(c)\cos(30)\]

Answer 4

or using law of sine
\[\frac{ \sin(A) }{ a }=\frac{ \sin(B) }{ b}\\\frac{\sin30}{4}=\frac{\sin(B)}{6}\\sin(B)=\frac{3}{4}\]

Answer 5

how can i get my answer from 3/4?

Answer 6

B=?

Answer 7

6

Answer 8

can you find B?

Answer 9

angle of B ?

Answer 10

i dont know how

Answer 11

B=48.5
or B=180-48.5

Answer 12

131.5?

Answer 13

thats not one of my answers?

Answer 14

is the answer 1?

Answer 15

i think its 2

Answer 16

then c=?
a=30
b=131.5 , b=48.5

Answer 17

number of possibilities is ?