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Geometry 7 Online
OpenStudy (anonymous):

area of a parallelogram did i do this right ?

OpenStudy (anonymous):

OpenStudy (anonymous):

i got 105?

geerky42 (geerky42):

Yeah 105 is correct answer.

geerky42 (geerky42):

what about unit?

OpenStudy (anonymous):

thanks and um that would be cm

geerky42 (geerky42):

No. \(\text{cm}\times\text{cm} = \text{cm}^2\), right?

geerky42 (geerky42):

Since you did \(7~\text{cm}\times 15~\text{cm}\)

OpenStudy (anonymous):

oh yes i forgot sorry

geerky42 (geerky42):

okay, so answer is \(105~\text{cm}^2\)

OpenStudy (anonymous):

ok so @geerky42 is this right

geerky42 (geerky42):

Unit is wrong

geerky42 (geerky42):

You did \(\dfrac{1}{2} (8~\text{cm}\times10~\text{cm}) \)

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so cm3

geerky42 (geerky42):

How?

OpenStudy (anonymous):

1/2 x 8 x 10

geerky42 (geerky42):

1/2 has no unit

OpenStudy (anonymous):

oh wait cm2

geerky42 (geerky42):

yeah

OpenStudy (anonymous):

ok

geerky42 (geerky42):

You can treat units like variable

geerky42 (geerky42):

\(\text{cm}\times\text{cm} = \text{cm}^2\) Just like how \(x\times x = x^2\)

OpenStudy (anonymous):

ah ok that makes more sense

OpenStudy (anonymous):

i see

OpenStudy (anonymous):

what about this

OpenStudy (anonymous):

@geerky42

geerky42 (geerky42):

Area should be \(3.14~\text{yd}^2\)

OpenStudy (anonymous):

how is that

geerky42 (geerky42):

Because you have \(\pi r^2\) So you squared unit too.

geerky42 (geerky42):

\[\pi r^2~~~\rightarrow~~~\pi(1~\text{yd})^2\]

OpenStudy (anonymous):

ohh

geerky42 (geerky42):

Yeah. What about circumference?

OpenStudy (anonymous):

ok and my circumference is 6.28yd2

geerky42 (geerky42):

why \(\text{yd}^2\)?

OpenStudy (anonymous):

2*3.14

geerky42 (geerky42):

\[2\pi r ~~~\rightarrow~~~2\pi(1~\text{yd})\]

geerky42 (geerky42):

that "2" has no unit.

OpenStudy (anonymous):

ah ok so circumference is usually 1pi

geerky42 (geerky42):

\[C = 2\pi (1~\text{yd})\]

geerky42 (geerky42):

So 6.28 yd

OpenStudy (anonymous):

yeah that's the formula i used

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

im not sure what to do here

geerky42 (geerky42):

It's basically semicircle subtract triangle

OpenStudy (anonymous):

if the radius is 6 that means the diameter is 12

OpenStudy (anonymous):

huh? so how do I start to solve

geerky42 (geerky42):

find area of triangle and area of semicircle, then you do semicircle - triangle

OpenStudy (anonymous):

ah ok onr sec

OpenStudy (anonymous):

wait but only the height is given for the triangle how would i find the base

geerky42 (geerky42):

|dw:1433376534008:dw|

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