Geometry
7 Online
OpenStudy (anonymous):
area of a parallelogram did i do this right ?
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OpenStudy (anonymous):
OpenStudy (anonymous):
i got 105?
geerky42 (geerky42):
Yeah 105 is correct answer.
geerky42 (geerky42):
what about unit?
OpenStudy (anonymous):
thanks and um that would be cm
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geerky42 (geerky42):
No.
\(\text{cm}\times\text{cm} = \text{cm}^2\), right?
geerky42 (geerky42):
Since you did \(7~\text{cm}\times 15~\text{cm}\)
OpenStudy (anonymous):
oh yes i forgot sorry
geerky42 (geerky42):
okay, so answer is \(105~\text{cm}^2\)
OpenStudy (anonymous):
ok so @geerky42 is this right
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geerky42 (geerky42):
Unit is wrong
geerky42 (geerky42):
You did \(\dfrac{1}{2} (8~\text{cm}\times10~\text{cm}) \)
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so cm3
geerky42 (geerky42):
How?
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OpenStudy (anonymous):
1/2 x 8 x 10
geerky42 (geerky42):
1/2 has no unit
OpenStudy (anonymous):
oh wait cm2
geerky42 (geerky42):
yeah
OpenStudy (anonymous):
ok
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geerky42 (geerky42):
You can treat units like variable
geerky42 (geerky42):
\(\text{cm}\times\text{cm} = \text{cm}^2\)
Just like how \(x\times x = x^2\)
OpenStudy (anonymous):
ah ok that makes more sense
OpenStudy (anonymous):
i see
OpenStudy (anonymous):
what about this
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OpenStudy (anonymous):
@geerky42
geerky42 (geerky42):
Area should be \(3.14~\text{yd}^2\)
OpenStudy (anonymous):
how is that
geerky42 (geerky42):
Because you have \(\pi r^2\)
So you squared unit too.
geerky42 (geerky42):
\[\pi r^2~~~\rightarrow~~~\pi(1~\text{yd})^2\]
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OpenStudy (anonymous):
ohh
geerky42 (geerky42):
Yeah. What about circumference?
OpenStudy (anonymous):
ok and my circumference is 6.28yd2
geerky42 (geerky42):
why \(\text{yd}^2\)?
OpenStudy (anonymous):
2*3.14
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geerky42 (geerky42):
\[2\pi r ~~~\rightarrow~~~2\pi(1~\text{yd})\]
geerky42 (geerky42):
that "2" has no unit.
OpenStudy (anonymous):
ah ok so circumference is usually 1pi
geerky42 (geerky42):
\[C = 2\pi (1~\text{yd})\]
geerky42 (geerky42):
So 6.28 yd
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OpenStudy (anonymous):
yeah that's the formula i used
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
im not sure what to do here
geerky42 (geerky42):
It's basically semicircle subtract triangle
OpenStudy (anonymous):
if the radius is 6 that means the diameter is 12
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OpenStudy (anonymous):
huh? so how do I start to solve
geerky42 (geerky42):
find area of triangle and area of semicircle, then you do
semicircle - triangle
OpenStudy (anonymous):
ah ok onr sec
OpenStudy (anonymous):
wait but only the height is given for the triangle how would i find the base
geerky42 (geerky42):
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