Question

Simplify completely: square root of 81y^5

Answer 1

59049

Answer 2

i dont think that is what i need sorry.

Answer 3

options:
A. 9y^2 square root y
B. 3y^2
C. 3y^2 square root 2y
D. 9y square root y

Answer 4

ok

Answer 5

why?

Answer 6

ok i think that makes sense

Answer 7

ok thanks!

Answer 8

Whats the square root of 81?

Answer 9

9

Answer 10

good \[\huge~9*(y*y*y*y*y)\]

Answer 11

\[\sqrt{81y^{5}} = \sqrt{81}*\sqrt{y^{4}}*\sqrt{y}\]
You can think of it like this, which seems to be the approach of pooja above. Good luck :)

Answer 12

9y

Answer 13

9y square root y?

Answer 14

@pooja195

Answer 15

I agree with that. @Concentrationalizing is it right though? :/

Answer 16

Well, given \[\sqrt{81y^{5}} = \sqrt{81} * \sqrt{y^{4}} * \sqrt{y}\]
\(\sqrt{81} = 9\)

For the \(\sqrt{y^{4}}\) part, if we think of the square root as being an exponent of 1/2, we have:
\[\sqrt{y^{4}} = y^{4*\frac{1}{2}} = y^{2}\]
The \(\sqrt{y}\) part cannot be simplified. Put it all together and we have

\(9y^{2}\sqrt{y}\)

Answer 17

i think i understand that, Thank you!

Answer 18

Of course :)