Question

Halp.

Answer 1

@zepdrix

Answer 2

can you help? :)

Answer 3

AHHHH I'm too tiredddddd -_-
what's going on now?
are the ones you filled in already, correct? you think so?

Answer 4

Yeah I think they're correct, but not for sure.
aww i'm sorry you're tired D:

Answer 5

What is c..?

Answer 6

c^2=a^2+b^2
c^2=36+64
oh..so 10

Answer 7

o, ok that looks better

Answer 8

\[\Large\rm P=\left(10,\frac{32}{3}\right),\qquad F_1=(-6,0),\qquad F_2=(6,0)\]So use your distance formula, ya?

Answer 9

we can just use the p point like that?

Answer 10

how do we use the distance formula here? :o

Answer 11

\[\Large\rm d(P,F_1)=\sqrt{(10--6)^2+\left(\frac{32}{3}-0\right)^2}\]ya? :d

Answer 12

Shouldn't the focus points be related to the c values?
Hmm sec, reading up on some of this stuff >.<

Answer 13

\[\sqrt{256+\frac{ 1024 }{ 9 }}\]

Answer 14

?

Answer 15

err, dangit. Yeah I think.
So it would be
f1= (-10,0)
f2=(10,0)

Answer 16

so that changes this next part we just did. oopsies.

Answer 17

oh true :3 heh

Answer 18

soo I think d(p, f1) = 68

Answer 19

\[\Large\rm P=\left(10,\frac{32}{3}\right),\qquad F_1=(-10,0),\qquad F_2=(10,0)\]Really? Hmm I'm getting something more like this,\[\Large\rm d(P,F_1)=\sqrt{(10--10)^2+\left(\frac{32}{3}-0\right)^2}\approx 22.7\]

Answer 20

\[=\sqrt{(10+10)^2+(\frac{ 32 }{ 3 }-0)^2}\]
\[\sqrt{400+\frac{ 1024 }{ 9 }}\]
Put 400/9
then add them up and apply sq root
= 68

Answer 21

I messed up somewhere really bad, yeah? o.o

Answer 22

\[\Large\rm =\sqrt{400+113.8}=\sqrt{513.8}\approx 22.7\]Still not sure how you're getting 68 :) lol

Answer 23

Oh oh oh i see what You did, no no no.
not 400/9
you have to multiply the top by 9 as well if u want to do it that way.
400 = (400*9)/9 = 3600/9

Answer 24

yeah yeah I thought i did that :o

Answer 25

that mistake would have given you a number smaller than 22.7 though
lol so i'm not sure what's going on ;0

Answer 26

lol me neither. Ah well. moving on then xD

Answer 27

erm so it says put exact interger. but the answer is 22.7 should i round it to 23 do you think?

Answer 28

Oh it says exact?
Ok then uhhh

Answer 29

oh sorry, sorry. it says "exact interger, fraction, or decimal"

Answer 30

so that would be.. 3 numbers after the decimal point? o.0

Answer 31

\[\Large\rm d=\sqrt{\frac{3600}{9}+\frac{1024}{9}}=\frac{68}{3}\]Is that where the 68 was coming from? 0_o

Answer 32

oh! there it is xD

Answer 33

I completely forgot the 3 lol

Answer 34

how bout the other distance? :)

Answer 35

would that answer be 22.666? or just two 6's?

Answer 36

the other distance = 10.66?

Answer 37

68/3 is a better form of the solution.
if you want a decimal with three places though, it would be 22.667

Answer 38

yes, the other distance is 32/3
:)

Answer 39

or 22.67 for two decimals

Answer 40

ee the feeling of accomplishment haha yay!
I'm going to try the fraction form first.

Answer 41

last box!

Answer 42

\[\Large\rm \frac{68}{3}-\frac{32}{3}=?\]Fractions seem better.
Makes this last step easier.

Answer 43

36/3!

Answer 44

:P

Answer 45

36 over 3 factorial? :o
no that can't be right.

jk :x hehehe

Answer 46

noooo =.= haha
it's 12 then xD

Answer 47

does 12 fit the form of 2(a)?
where a=6?

Answer 48

naaaah

Answer 49

jk, yes

Answer 50

12 = 2(6)

yayyy you did it \c:/ good job!

Answer 51

wait so in that last box I put 12 again?

Answer 52

no..it would be 6 in that box

Answer 53

ya 6 :O

Answer 54

lol I was like WAIT that doesn't make sense xD
yaya *we* did it!! :) ty ty

Answer 55

ook let's see if it's all correct.

Answer 56

yep yep it's all correct :*

Answer 57

yay \c:/

Answer 58

want to help with another one? though it is quitee extensive