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Mathematics 17 Online
OpenStudy (anonymous):

Find the exact value of each expression: a. sin20degcos80de-cos20degsin80deg b. cos 5pi/12cos7pi/12-sin5pi/12sin7pi/12

OpenStudy (anonymous):

@jim_thompson5910 does that make sense or should i write out again?

jimthompson5910 (jim_thompson5910):

you don't need to write "deg"

jimthompson5910 (jim_thompson5910):

hint: see page 2 of http://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf specifically the "Sum and Difference Formulas" section

OpenStudy (anonymous):

so it would be the formula stating that sin(a +or-b)=sinacosb-cosasinb?

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

you'll use the cosine version for part b

OpenStudy (anonymous):

oh okay so for the test tomorrow I should just memorize those formulas? but so now to solve it, it would be (20+80) or (20-80)? so the answer is 100 or -60?

jimthompson5910 (jim_thompson5910):

sin(20)cos(80)-cos(20)sin(80) = sin(20-80) = sin(-60) = ???

OpenStudy (anonymous):

oh wait oops

OpenStudy (anonymous):

would it be sin(60)?

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

sin(-60) is not equal to sin(60)

OpenStudy (anonymous):

oh .. i thought you put the question marks as in that it was wrong

jimthompson5910 (jim_thompson5910):

no it's my way of putting a blank

OpenStudy (anonymous):

it's pi/3

jimthompson5910 (jim_thompson5910):

so you'd fill in the blank

OpenStudy (anonymous):

ohh ok sorry

jimthompson5910 (jim_thompson5910):

sin(-60) = -sin(60) = _______________

OpenStudy (anonymous):

-pi/3

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

no not -pi/3

jimthompson5910 (jim_thompson5910):

you're thinking of -60 degrees = -pi/3 radians

jimthompson5910 (jim_thompson5910):

use the unit circle and determine -sin(60)

OpenStudy (anonymous):

okay i've been looking at the unit circle for 5 minutes and because you're determining -sin60 you would be looking in the 3 and fourth quadrants right?

OpenStudy (anonymous):

and looking for a distance of 60 degrees the opposite way? I'm just trying to remember what my teacher said.. He said something like that @jim_thompson5910

jimthompson5910 (jim_thompson5910):

|dw:1433398564125:dw|

jimthompson5910 (jim_thompson5910):

|dw:1433398585790:dw|

jimthompson5910 (jim_thompson5910):

|dw:1433398602906:dw|

jimthompson5910 (jim_thompson5910):

determine the y coordinate of that point, then make it negative that will be the value of -sin(60)

OpenStudy (anonymous):

root 3/2?

jimthompson5910 (jim_thompson5910):

\[\Large \sin(60) = \frac{\sqrt{3}}{2}\] \[\Large -\sin(60) = -\frac{\sqrt{3}}{2}\]

OpenStudy (anonymous):

okay so I just look for it on the unit circle and determine it through the coordinate?

jimthompson5910 (jim_thompson5910):

yes, x = cos(theta) and y = sin(theta)

OpenStudy (anonymous):

ok! got it!

OpenStudy (anonymous):

now for part b do you find pi/6 on the unit circle and look at x coordinate to determine the value?

OpenStudy (anonymous):

@jim_thompson5910

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