-2x² - 7 = 4x

Where are a, b, and c in this equation? How do I solve this with the quadratic equation?

Question

-2x² - 7 = 4x

Where are a, b, and c in this equation?  How do I solve this with the quadratic equation?

jamierox4ev3r · Answer

remember, a standard quadratic equation is always in this form:

$a^{2}x+bx+c$

so you're going to need to manipulate this equation to set it to this formula

anonymous · Answer

Is a 2?  Is b 4?  Is C 7?

butterflydreamer · Answer

we have this equation:
-2x² - 7 = 4x 
We need to rearrange it so that the x² part is positive.
Therefore take the "-2x² - 7" to the other side of the equals sign and we get:
-2x² - 7 = 4x 
0 = 2x² + 4x +7

Standard form is :
ax² + bx + c = 0
Therefore match it up with your equation and we get:
a = 2, b = 4 , c = 7
Which you said.. so you're correct ^_^!

anonymous · Answer

How do I solve this?

anonymous · Answer

use this formula$$x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }$$

butterflydreamer · Answer

yeah use the quadratic formula (as stated by surjithayer) to solve for x :)

anonymous · Answer

1.58?

butterflydreamer · Answer

not quite
we know a = 2, b = 4 and c = 7
plug these values into the quadratic formula:
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