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Mathematics 11 Online
OpenStudy (anonymous):

The figure below shows a shaded circular region inside a larger circle: A shaded circle is shown inside another larger circle. The radius of the smaller circle is labeled as r and the radius of the larger circle is labeled as R. On the right side of the image is written r equal to 3 inches and below r equal to 3 inches is written R equal to 5 inches. What is the probability that a point chosen inside the larger circle is not in the shaded region? 24% 36% 50% 64%

OpenStudy (anonymous):

@Jamierox4ev3r

OpenStudy (anonymous):

@Jamierox4ev3r

OpenStudy (anonymous):

HanAkoSolo (jamierox4ev3r):

shoot I'm not sure about the whole probability thing x'D

HanAkoSolo (jamierox4ev3r):

but you could solve for area. and then make those ratios

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

@whpalmer4

OpenStudy (anonymous):

@iGreen

HanAkoSolo (jamierox4ev3r):

oh wait nvm i remember x'D lol sorry

OpenStudy (anonymous):

ok

HanAkoSolo (jamierox4ev3r):

so yeah. find area. the formula is \(\pi r^{2}\)

HanAkoSolo (jamierox4ev3r):

let's start with the smaller circle: \(A=\pi r^{2}\) A=\(\pi 3^{2}\)

HanAkoSolo (jamierox4ev3r):

so multiply pi by 2.... what do you get? @Marc1313

OpenStudy (anonymous):

3.14 by 2?

OpenStudy (anonymous):

6.28

HanAkoSolo (jamierox4ev3r):

i meant by 9..lol sorry xD since \(3^[2]\) is 9

OpenStudy (anonymous):

28.26

HanAkoSolo (jamierox4ev3r):

**\(3^{2}\)

HanAkoSolo (jamierox4ev3r):

yep. so that's the area of the smaller circle

HanAkoSolo (jamierox4ev3r):

can you find me the area of the larger circle?

OpenStudy (anonymous):

how

OpenStudy (anonymous):

this is confusing

HanAkoSolo (jamierox4ev3r):

just do it with this formula i used earlier \(A=\pi r^{2}\) \(A=pi 5^{2}\) which becomes \(A=\pi 25\)

HanAkoSolo (jamierox4ev3r):

multiply pi by 25 to find the area of the larger circle

HanAkoSolo (jamierox4ev3r):

@Marc1313 can you multiply pi by 25 to find the area of the larger circle?

OpenStudy (anonymous):

85

OpenStudy (anonymous):

@Jamierox4ev3r

HanAkoSolo (jamierox4ev3r):

actually, 78.54

HanAkoSolo (jamierox4ev3r):

but close :)

HanAkoSolo (jamierox4ev3r):

there's one final step to find the answer...set the areas as a ratio, like so: \(\Large\frac{28.27}{78.54}\) ^^ then simplify it :)

OpenStudy (anonymous):

78.5

OpenStudy (anonymous):

36%

HanAkoSolo (jamierox4ev3r):

yep :) make sense?

OpenStudy (anonymous):

a little

OpenStudy (anonymous):

are you sure that si the answer

HanAkoSolo (jamierox4ev3r):

cool. basically, find the areas, and then make a ratio (fancy way of saying division) :)

HanAkoSolo (jamierox4ev3r):

positive. I remember this unit now, lol i realized that it wasn't probability, it was just ratios :P

OpenStudy (anonymous):

Thank you so much next question

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