The figure below shows a shaded circular region inside a larger circle:
A shaded circle is shown inside another larger circle. The radius of the smaller circle is labeled as r and the radius of the larger circle is labeled as R. On the right side of the image is written r equal to 3 inches and below r equal to 3 inches is written R equal to 5 inches.
What is the probability that a point chosen inside the larger circle is not in the shaded region?
24%
36%
50%
64%
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OpenStudy (anonymous):
@Jamierox4ev3r
OpenStudy (anonymous):
@Jamierox4ev3r
OpenStudy (anonymous):
HanAkoSolo (jamierox4ev3r):
shoot I'm not sure about the whole probability thing x'D
HanAkoSolo (jamierox4ev3r):
but you could solve for area. and then make those ratios
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OpenStudy (anonymous):
@iGreen
OpenStudy (anonymous):
@whpalmer4
OpenStudy (anonymous):
@iGreen
HanAkoSolo (jamierox4ev3r):
oh wait nvm i remember x'D lol sorry
OpenStudy (anonymous):
ok
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HanAkoSolo (jamierox4ev3r):
so yeah. find area.
the formula is \(\pi r^{2}\)
HanAkoSolo (jamierox4ev3r):
let's start with the smaller circle:
\(A=\pi r^{2}\)
A=\(\pi 3^{2}\)
HanAkoSolo (jamierox4ev3r):
so multiply pi by 2.... what do you get? @Marc1313
OpenStudy (anonymous):
3.14 by 2?
OpenStudy (anonymous):
6.28
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HanAkoSolo (jamierox4ev3r):
i meant by 9..lol sorry xD since \(3^[2]\) is 9
OpenStudy (anonymous):
28.26
HanAkoSolo (jamierox4ev3r):
**\(3^{2}\)
HanAkoSolo (jamierox4ev3r):
yep. so that's the area of the smaller circle
HanAkoSolo (jamierox4ev3r):
can you find me the area of the larger circle?
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OpenStudy (anonymous):
how
OpenStudy (anonymous):
this is confusing
HanAkoSolo (jamierox4ev3r):
just do it with this formula i used earlier
\(A=\pi r^{2}\)
\(A=pi 5^{2}\)
which becomes
\(A=\pi 25\)
HanAkoSolo (jamierox4ev3r):
multiply pi by 25 to find the area of the larger circle
HanAkoSolo (jamierox4ev3r):
@Marc1313 can you multiply pi by 25 to find the area of the larger circle?
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OpenStudy (anonymous):
85
OpenStudy (anonymous):
@Jamierox4ev3r
HanAkoSolo (jamierox4ev3r):
actually, 78.54
HanAkoSolo (jamierox4ev3r):
but close :)
HanAkoSolo (jamierox4ev3r):
there's one final step to find the answer...set the areas as a ratio, like so:
\(\Large\frac{28.27}{78.54}\)
^^
then simplify it :)
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OpenStudy (anonymous):
78.5
OpenStudy (anonymous):
36%
HanAkoSolo (jamierox4ev3r):
yep :) make sense?
OpenStudy (anonymous):
a little
OpenStudy (anonymous):
are you sure that si the answer
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HanAkoSolo (jamierox4ev3r):
cool. basically, find the areas, and then make a ratio (fancy way of saying division) :)
HanAkoSolo (jamierox4ev3r):
positive. I remember this unit now, lol i realized that it wasn't probability, it was just ratios :P